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3 years ago

Solve for x. -- 2x + 6 = 30 - 6x -6 6 -8 8

Mathematics

2 answers:

dangina [55]3 years ago

7 0

$\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}$

-2x+6=30-6x

-2x+6x=30-6

(-2+6)x=24

4x=24

$\sf{x=\dfrac{24}{4} }$

quester [9]3 years ago

4 0

Answer:

Step-by-step explanation:

$-2x+6=30-6x\\\\4x+6=30\\\\4x=24\\\\x=6$

1. add 6x to both sides

2. subtract 6 from both sides

3. divide both sides by 4

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Point S is on line segment RT. Given RT=4x, ST = 5x-10, and RS = 6 determine the numerical length of ST.

Art [367]

Answer:

ST=10

Step-by-step explanation:

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3 years ago

Angle of a triangle measures 115° the other two angles are in the ratio of 4:9 what are the measures of those two angles

nasty-shy [4]

Answer:

20, 45

Step-by-step explanation:

A triangle has 180 degrees interior angle measure. One angle measure 115 so that means the other two angles must add up to 65.

The remaning angles form a ratio of 4:9. This means we must split 65 into a ratio of. 4:9

A ratio partition parts of something. We can add the ratio intergers to find it full length.

4+9=13.

Divide 65/13=5.

Multiply 5x4 and 5x9 serpately.

We get 20 and 45

6 0

3 years ago

Suppose the polynomial f(x) has the following end behavior: as x approaches infinity, f(x) approaches infinity, and as x approac

galina1969 [7]

Answer:

C. x³+10x²−5x+5

E. 7x⁵+4x²

F. x+8

Step-by-step explanation:

The graph they described should look something like the one i drew below.

So all you have to do is look at the number with the highest exponent.

If the exponent is an odd number and the x is positive then that function will have an end behavior like the picture i posted.

x³ is good

-x³ is bad because of the negative sign

x² is bad because exponent is even

x⁷ is good

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6 0

3 years ago

Use the discriminant to predict the nature of the solutions to the equation 4x-3x²=10. Then, solve the equation.

AleksandrR [38]

Answer:

Two imaginary solutions:

x₁= $\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

x₂ = $\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

Step-by-step explanation:

When we are given a quadratic equation of the form ax² +bx + c = 0, the discriminant is given by the formula b² - 4ac.

The discriminant gives us information on how the solutions of the equations will be.

If the discriminant is zero, the equation will have only one solution and it will be real
If the discriminant is greater than zero, then the equation will have two solutions and they both will be real.
If the discriminant is less than zero, then the equation will have two imaginary solutions (in the complex numbers)

So now we will work with the equation given: 4x - 3x² = 10

First we will order the terms to make it look like a quadratic equation ax²+bx + c = 0

So:

4x - 3x² = 10

-3x² + 4x - 10 = 0 will be our equation

with this information we have that a = -3 b = 4 c = -10

And we will find the discriminant: $b^{2} -4ac = 4^{2} -4(-3)(-10) = 16-120=-104$

Therefore our discriminant is less than zero and we know that our equation will have two solutions in the complex numbers.

To proceed to solve the equation we will use the general formula

x₁= (-b+√b²-4ac)/2a

so x₁ = $\frac{-4+\sqrt{-104} }{2(-3)} \\\frac{-4+\sqrt{-104} }{-6}\\\frac{-4+2\sqrt{-26} }{-6} \\\frac{-4+2i\sqrt{26} }{-6} \\\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

The second solution x₂ = (-b-√b²-4ac)/2a

so x₂= $\frac{-4-\sqrt{-104} }{2(-3)} \\\frac{-4-\sqrt{-104} }{-6}\\\frac{-4-2\sqrt{-26} }{-6} \\\frac{-4-2i\sqrt{26} }{-6} \\\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

These are our two solutions in the imaginary numbers.

7 0

3 years ago

A=c+(-10) Solve for c in terms of other variables.

True [87]

To do this we need to move 10 to other side. To accomplish this you just need to add 10 to both side since (-10)

so
A+ 10 = c -10 + 10
we get
A+ 10 = c

lets say it wasn't -10 but positive 10.

A = c + 10 then we would subtract 10 from both sides

A -10 = c + 10 - 10
we get
A - 10 = C

5 0

3 years ago

Solve for x. -- 2x + 6 = 30 - 6x -6 6 -8 8​

Solve for x. -- 2x + 6 = 30 - 6x -6 6 -8 8