Answer:
29
Step-by-step explanation:
Answer:
Assuming exercise 1 is the blob in the top left of your pic the center is four and mean of distribution is 2
Step-by-step explanation:
Do it yourself let’s go come on
Answer:
13/63
Step-by-step explanation:
7/9-4/7=49/63-36/63=13/63
Given:
Consider the height of the rocket, in feet after x seconds of launch is
![y=-16x^2+152x+74](https://tex.z-dn.net/?f=y%3D-16x%5E2%2B152x%2B74)
To find:
The time at which the rocket will reach its max, to the nearest 100th of a second.
Solution:
We have,
![y=-16x^2+152x+74](https://tex.z-dn.net/?f=y%3D-16x%5E2%2B152x%2B74)
It is a quadratic polynomial with negative leading coefficient. So, it is a downward parabola.
Vertex of a downward parabola is the point of maxima.
To find the time at which the rocket will reach its max, we need to find the x-coordinate of the vertex.
If a quadratic function is
, then the vertex is
![Vertex=\left(-\dfrac{b}{2a},f\left(-\dfrac{b}{2a}\right)\right)](https://tex.z-dn.net/?f=Vertex%3D%5Cleft%28-%5Cdfrac%7Bb%7D%7B2a%7D%2Cf%5Cleft%28-%5Cdfrac%7Bb%7D%7B2a%7D%5Cright%29%5Cright%29)
Here,
.
So,
![-\dfrac{b}{2a}=-\dfrac{152}{2(-16)}](https://tex.z-dn.net/?f=-%5Cdfrac%7Bb%7D%7B2a%7D%3D-%5Cdfrac%7B152%7D%7B2%28-16%29%7D)
![-\dfrac{b}{2a}=-\dfrac{152}{-32}](https://tex.z-dn.net/?f=-%5Cdfrac%7Bb%7D%7B2a%7D%3D-%5Cdfrac%7B152%7D%7B-32%7D)
![-\dfrac{b}{2a}=4.75](https://tex.z-dn.net/?f=-%5Cdfrac%7Bb%7D%7B2a%7D%3D4.75)
So, x-coordinate of the vertex is 4.75.
Therefore, the rocket will reach its max at 4.75 second.