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Andrej [43]
3 years ago
15

DAY 5 PLEASE HELP i dont get it

Mathematics
2 answers:
stepladder [879]3 years ago
5 0
If 18 inches is 20% less than the original length of the snake, then you can say that it is 80% of the original length. 18 inches ÷ 80% = 0.225, which would be 1% of the original snake. Now that you have 1%, all you need to do is multiply by 100 to get 100%, which is 22.5 inches, which is answer D. I hope this helps!
sveticcg [70]3 years ago
3 0
3.6 inches, you just multiply 20% x 18.
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Which undefined geometric term is described as a location on a coordinate plane that is designated by an ordered
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Answer:

d- point

Step-by-step explanation:

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3 years ago
Julie hung up 3 bird feeders in her yard each birdfeeder,has 12 perches how many perches are there altogether
Sedaia [141]
36 perches altogether.

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6 0
3 years ago
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Which equation represents the relationship between the x-and y-values shown in the table?
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Y=3x-4

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5 0
3 years ago
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A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and
mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

\mu = \frac{3X_{1} + 4X_{2}  }{8}

Now

Bias for the estimator = E(μ bar) - μ

                                    = E( \frac{3X_{1} + 4X_{2}  }{8}) - 4.5

                                    = \frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5

                                    = \frac{3(4.5) + 4(4.5)}{8} - 4.5

                                    = \frac{13.5 + 18}{8} - 4.5

                                    = \frac{31.5}{8} - 4.5

                                    = 3.9375 - 4.5

                                    = - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

                                                             = Var(μ bar) + [Bias(μ bar, μ)]²

                                                             = Var( \frac{3X_{1} + 4X_{2}  }{8}) + 0.3136

                                                             = \frac{1}{64} Var( {3X_{1} + 4X_{2}  }) + 0.3136

                                                             = \frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})]  }) + 0.3136

                                                             = \frac{1}{64} [{3(57.76) + 4(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [7(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [404.32]  } + 0.3136

                                                             = 6.3175 + 0.3136

                                                              = 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0
3 years ago
Please help me with this problem
Alexus [3.1K]
(a) It is leaking 18 liters per minute.

Explanation : From 15 minutes to 20 minutes, your starting point at 15 is 590 liters and at 20 you have exactly 500. Next you have 25 which is now at 410. So it's leaking 90 liters every five minutes, so of course dividing the two (90 ÷ 5) you get 18.

(a)² it increases for about the same time that it would decrease of course.

(b) The vat started at 860 liters before they started draining it.

Explanation : Well, all it takes is just working backwards, add 90 liters to the liters at 15 minutes and deduct five minutes from 15. Do this process until you arrive at 0. It's simple
7 0
4 years ago
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