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4 years ago

The function f is defined by f(x)=200÷x−b, where b is a constant. Find b, if the value of f at x= 1/3 is equal to 150.

Mathematics

1 answer:

Ghella [55]4 years ago

4 0

Answer:

b = 450

Step-by-step explanation:

You want b when ...

150 = (200/(1/3)) -b

b = 3·200 -150 = 450 . . . . . add b-150, simplify

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What is the lowest common mutiple of 6 and 9

Lilit [14]

Answer:

Step-by-step explanation:

$9 = 3 \times 3 \\ 6 = 2 \times 3 \\ common \: factor = 3 \\ uncommon \: factors = 2, \: 3 \\ lcm = common \times uncommon \: factors \\ = 3 \times 2 \times 3 = 18$

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4 years ago

The radius of a circle is 6 in. Find the circumference to the nearest tenth.

ycow [4]

Answer:

37.7

Step-by-step explanation:

The orginal answer is 37.699

But you want to round the tenth

So 9 to the 6 you want to rasie the score

6 turns into a 7 and the numbers behind it (9 and the other 9) turn into a zero

37.7 or 37.700

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3 years ago

Two fifths times ten

babymother [125]

2/5 * 10 = 2/5 * 10/1 = 20/5 = 4

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3 years ago

Read 2 more answers

Find the limit of the following sequence or determine that the limit does not exist. {5n/Squareroot 81 n^2 + 5} Select the corre

elixir [45]

Answer:

C. The sequence is monotonic and bounded. The limit is 5/9

Step-by-step explanation:

For this case we have the following n term:

$a_n = \frac{5n}{\sqrt{81n^2 +5}}$

And we can find the limit when x tend to infinity:

$\lim_{n\to\infty} \frac{5n}{\sqrt{81n^2 +5}}$

And we got this:

$5 \lim_{n\to\infty} \frac{n}{\sqrt{81n^2 +5}}$

Now we can divide by n the numerator and denominator like this:

$5 \lim_{n\to\infty} \frac{1}{\sqrt{81 +\frac{5}{n^2}}}$

And now we can apply properties of limits and we got this:

$5 \frac{\lim_{n\to\infty} 1}{\lim_{n\to\infty} \sqrt{81 +\frac{5}{n^2}}}$

And we got:

$5 \frac{1}{9}=\frac{5}{9}$

So then our sequence is bounded by $\frac{5}{9}$

By definition a monotonic sequence is a "sequence that is always increasing or decreasing".

For this case if we find:

$a_1 = \frac{5}{\sqrt{86}}$

$a_2 = \frac{10}{\sqrt{329}}$

We see that $a_2 >a_1$ and in general we see that $a_n >a_{n-1}$ . So then the ebst answer for this case is:

C. The sequence is monotonic and bounded. The limit is 5/9

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4 years ago

What is the domain for x is less than or equal to 5

arsen [322]

Answer:

54321

Step-by-step explanation:

or any negative number

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4 years ago