Answer:
20%
Step-by-step explanation:
You have to do 5/25, giving you 20%.
Answer:
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Class 9
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>>Quadrilaterals
>>Quadrilaterals and Their Various Types
>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2
Question
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In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28
0
and ∠QRT=65
0
, then find the values of x and y.
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Medium
Solution
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Given, PQ⊥PS,PQ∥SR,∠SQR=28
∘
,∠QRT=65
∘
According to the question,
x+∠SQR=∠QRT (Alternate angles as QR is transversal.)
⇒x+28
∘
=65
∘
⇒x=37
∘
Also ∠QSR=x
⇒∠QSR=37
∘
Also ∠QRS+∠QRT=180
∘
(Linear pair)
⇒∠QRS+65
∘
=180
∘
⇒∠QRS=115
∘
Now, ∠P+∠Q+∠R+∠S=360
∘
(Sum of the angles in a quadrilateral.)
⇒90
∘
+65
∘
+115
∘
+∠S=360
∘
⇒270
∘
+y+∠QSR=360
∘
⇒270
∘
+y+37
∘
=360
∘
⇒307
∘
+y=360
∘
⇒y=53
∘
Step-by-step explanation:
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Answer:
V = 882pi units^3
or approximately
2769.48 units^3
Step-by-step explanation:
The column of a cylinder is given by
V = pi * r^2 * h
We know the radius is 7 and the height is 18
V = pi * 7^2 *18
V =pi *49 *18
V =882 pi
If we want an approximate answer, we can approximate pi by 3.14
V = 3.14 * 882
V =2769.48
Answer:
5.7
Step-by-step explanation:
Delta math
C=2/5 with syptolis thereon so 2/5(C5/9) is the abswer for C (F-32)= hypoteticulos syptolis F-25/32(-32/35) this the answer for (F-32)
