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kompoz [17]
3 years ago
9

Please help me solve both of them

Mathematics
2 answers:
Kaylis [27]3 years ago
6 0

Answer:

first one: a,d,e

second one: d

Step-by-step explanation:

pemdas

lyudmila [28]3 years ago
6 0

Answer:

1.- A

2.- A

Step-by-step explanation:

You might be interested in
-3v=195<br><br> -45<br> 45<br> 65<br> -65<br> i think it is -45
mylen [45]

Answer:

-65 is your answer

Step-by-step explanation:

What you do is you divide -3 to both sides.

195/-3=-65.

-65 is your answer.

8 0
3 years ago
Read 2 more answers
Anyone knows #3 and 4 answers ?
UNO [17]
3.saven. 4.2and5 Third
4 0
3 years ago
(1/4) to the 3rd power
Ksivusya [100]
(1/4)=0.25
0.25*0.25*0.25=0.015625
6 0
3 years ago
Read 2 more answers
suppose a population of 250 crickets doubles in size every six months. How many crickets will there be after two years?
lord [1]

double every 6 months 

in 6 months there would be 250*2 = 500 crickets

 in 1 year there would be 500*2 = 1000 crickets

in 1.5 years there would be 1000 *2 = 2000 crickets

 in 2 years there would be 2000 *2 = 4000 crickets

4 0
3 years ago
Four diners have ordered a platter of desserts. The platter holds 8 chocolate chip cookies and 4 slices of chocolate cheesecake.
Furkat [3]

Answer:

P(Y>1 \cap Y

And we can find this probability like this:

P(Y>1 \cap Y

And we can replace the values and we got:

P(Y>1 \cap Y

Step-by-step explanation:

For this case we define the random variable Y as: the number of slices of cheesecake left on the platter after the first serving. And we have the following distribution for Y:

Y     |     0          1        2         3         4

P(Y) | 0.005  0.114  0.429  0.381  0.071

And we want to find the following probability:

P(Y>1 \cap Y

And we can find this probability like this:

P(Y>1 \cap Y

And we can replace the values and we got:

P(Y>1 \cap Y

3 0
3 years ago
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