The math club must sell 50 pies in order to reach the goal of 200 dollars
24= 3*2^3
88= 11*2^3
664= 83*2^3 -> 83=11+72 = 11 + 2^3*3^2
664=2^3 (11+2^3*3^2) = 88 +(2^3*2^3*3^2) = 88 +(24^2)
8408= 1051 * 2^3 -> 1051= 83+968 -> 968 = 2^3 * 11^2
8408= 2^3 (83+2^3*11^2) = 664 +(2^3*2^3*11^2) = 664 +(88^2)
So:
a(n) = a(n-1) + a(n-2)^2
Lets check: 88+24^2= 664
664+88^2= 8408
9514 1404 393
Answer:
x = 5.4
Step-by-step explanation:
The segment sum theorem tells you ...
AB +BC = AC
36 +(5x -9) = 54
5x = 27 . . . . . . . . . . . subtract 27 from both sides
x = 5.4 . . . . . . . . . . divide by 5
Answer: A/D
Step-by-step explanation:
