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Jet001 [13]
3 years ago
6

Give a rule for determining whether a fraction will be a terminating or repeating decimal.

Mathematics
2 answers:
svlad2 [7]3 years ago
8 0
Irrational, repeating decimal
lys-0071 [83]3 years ago
6 0

Answer:

irrational

Step-by-step explanation:

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husbands ten to have winve whose age is 85% of their own

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You earn $1,600 per pay period. Your deductions are $110, $66, and $14. What is your net pay?
hodyreva [135]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
Complete the tasks and answer the questions. Use the 2SD method to estimate the true proportion of the population of your city t
kupik [55]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Using 2SD Method

The confidence interval is

     The interval notation :  (0.108 ,  0.212 )

     The interval notation and the sample proportion ± the margin of error

     notation:0.16 \pm  0.052

 The  interpretation

    There is  95% confidence that the true proportion of those that dislike  cilantro lie within the upper(0.212) and the lower(0.108) limit of the calculate confidence interval

Using theory-based method      

      The 95% confidence interval is

            The interval notation :   (0.109 ,  0.211 )

     The interval notation and the sample proportion ± the margin of error

     notation:0.16 \pm  0.051

 The  interpretation

      There is  95% confidence that the true proportion of those that dislike  cilantro lie within the upper(0.211) and the lower(0.109) limit of the calculate confidence interval

Using theory-based method  

 The 88% confidence interval is  

         The interval notation :   (0.120 ,  0.200 )

          The interval notation and the sample proportion ± the margin of

           error notation:   0.16 \pm 0.040

The interpretation is

  There is  88% confidence that the true proportion of those that dislike  cilantro lie within the upper(0.200 ) and the lower(0.120) limit of the calculate confidence interval.

Step-by-step explanation:

From the question we are told that

The number sample size is n = 200

The number of people that dislike cilantro is k = 32

Generally the sample proportion is mathematically represented as

\r p = \frac{k}{N}

=> \r p = \frac{32}{200}

=> \r p = 0.16

Generally 2SD confidence interval is mathematically represented as

\r p  \pm 2\sqrt{\frac{\r p(1 - \r p)}{n} }

substituting value

0.16 \pm 2\sqrt{\frac{0.16(1 - 0.16)}{200} }

=> 0.16 \pm  0.052

This can also be represented as

(0.16 -  0.052 ,  0.06 + 0.052)

=> (0.108 ,  0.212 )

Generally this confidence interval can be interpreted as

There is 95% confidence that the true proportion of those that dislike cilantro lie within the upper and the lower limit of the calculate confidence interval

Using theory-based method estimate 95% confidence interval

Generally from the question the confidence level is 95% hence the level of significance is calculated as

\alpha  =  (100 - 95)\%

=> \alpha  =  0.05

The critical value of \frac{\alpha }{2} from the normal distribution table is

Z_{\frac{\alpha }{2} }  = 1.96

Generally the confidence level using theory base method is

0.16 \pm  1.96 \sqrt{\frac{0.16 (1- 0.16)}{200} }

=>     0.16 \pm 0.051

This can also be represented as

(0.16 -  0.051 ,  0.06 + 0.051)

=> (0.109 ,  0.211 )

Generally this confidence interval can be interpreted as

There is 95% confidence that the true proportion of those that dislike cilantro lie within the upper(0.211) and the lower(0.109) limit of the calculate confidence interval

Using theory-based method estimate 88% confidence interval

Generally from the question the confidence level is 95% hence the level of significance is calculated as

\alpha  =  (100 - 88)\%

=> \alpha  =  0.12

The critical value of \frac{\alpha }{2} from the normal distribution table is

Z_{\frac{\alpha }{2} } =Z_{\frac{0.12 }{2} } = 1.55

Generally the confidence level using theory base method is

0.16 \pm  1.55 \sqrt{\frac{0.16 (1- 0.16)}{200} }

=>     0.16 \pm 0.040

This can also be represented as

(0.16 -  0.040 ,  0.06 + 0.040)

=> (0.120 ,  0.200 )

Generally this confidence interval can be interpreted as

There is 88% confidence that the true proportion of those that dislike cilantro lie within the upper(0.200 ) and the lower(0.120) limit of the calculate confidence interval

3 0
4 years ago
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