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faltersainse [42]
3 years ago
5

See photo/ will give 10 points.

Mathematics
1 answer:
leonid [27]3 years ago
5 0

Answer:

B) Multiply by 3/2 on both sides of the equation by the multiplication property of equality

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
My name is Ann [436]

x = 2  \\ y = 7

is the answer to:

y = 11 - 2x \\ 4x - 3y =  - 13

_________________________________________

x = 5 \\ y = 2

is the answer to:

2x + y = 12 \\ x = 9 - 2y

_________________________________________

x = 3 \\ y = 5

is the answer to:

2x + y = 11 \\ x - 2y =  - 7

_________________________________________

x = 7 \\ y = 3

is the answer to:

x + 3y = 16 \\ 2x - y = 11

3 0
3 years ago
Complete the table using the Linear model: y = 2x + 1
Viefleur [7K]
Tried my best to plot it:)

8 0
3 years ago
4x+2y=-24<br> -4x+y = 12
allsm [11]

Answer:

Step-by-step explanation:

                                4x+2y = -24    -------------(i)

                              <u>  -4x+y =  12    -</u>------------(ii)

add (i) &(ii)                      3y = -12

                                         y = -12/3

                                         y = -4

Put y = (-4) in (i)

4x + 2*(-4) = -24

4x - 8 = -24

4x = -24 + 8

4x = -16

x = -16/4

x = -4

6 0
3 years ago
In the figure below X is best described as a
PolarNik [594]

Answer:

Idk

Step-by-step explanation:

Idk

5 0
3 years ago
In contract negotiations between a local government agency and its workers,
Liono4ka [1.6K]

Answer:

a. 0.4

b. Not independent.

Step-by-step explanation:

a. We use the probability table attached below for our calculations.

-the probability that an agreement is reached on both sides is obtained from the table:

P(Agreement)=\frac{400}{1000}\\\\\\=0.4

b. To determine whether the two events are independent, we compare the probabilities P(s)\times P(i) and P(s \ and \ i) where i denotes insurance and s denotes salaries:

P(s)\times P(i)=0.5\times 0.7\\\\=0.35\\\\\\P(s \ and \ i)=0.4

Two events are considered to be independent, if and only if:

P(A).P(B)=P(A\ and \ B)\\\\=>P(s).P(i)\neq P(s\ and\  i)

Hence, the events are not independent.

8 0
3 years ago
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