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Rasek [7]
3 years ago
7

In △JKL, solve for x. 74.89 30.29 38.16 66.73

Mathematics
2 answers:
Artist 52 [7]3 years ago
8 0
X = 34/cos27° = 34/0.891 ≈ 38.16
vovangra [49]3 years ago
5 0

Answer:

x=38.16\ units

Step-by-step explanation:

we know that

In the right triangle JKL

cos(27\°)=\frac{KL}{JL}

we have

KL=34\ units

JL=x\ units

substitute the values

cos(27\°)=\frac{34}{x}

x=\frac{34}{cos(27\°)}=38.16\ units

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Find the 64th term of the arithmetic sequence
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Answer:

The 64th term of the arithmetic sequence is -1075.

Step-by-step explanation:

Arithmetic sequence:

In an arithmetic sequence, the difference between consecutive terms, called common difference, is always the same.

The nth term of an arithmetic sequence is given by:

a_n = a_1 + (n-1)d

In which a_1 is the first term.

−4,−21,−38

First term -4, so a_1 = -4

Common difference of d = -38 - (-21) = -21 - (-4) = -17

Thus

a_n = a_1 + (n-1)d

a_n = -4 - 17(n-1)

Find the 64th term of the arithmetic sequence

This is a_{64}. So

a_n = -4 - 17(n-1)

a_{64} = -4 - 17(64-1) = -4 - 1071 = -1075

The 64th term of the arithmetic sequence is -1075.

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3 years ago
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0.00777x4.5/270,000 write in scientific notation
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Let's do it part by part:

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