Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so

we have

substitute



therefore
The area of triangle K is 16 times greater than the area of triangle J
Answer:
23
Step-by-step explanation:
we are given that angle NRQ is 78 degrees
we can see from the figure that the sum of the given angles is angle NRQ
so
(8x + 7) + (4x - 1) = 78
12x + 6 = 78
12x = 72
x = 6
Now, we have to find angle PRQ
replacing x with 6 in the equation of angle PRQ
PRQ = 4(6) - 1
PRQ = 23
Answer:
1- 4x -7 =29, x= 9
2-x/3 - 8 = 12, x=60
Step-by-step explanation:
4x-7 =29
4x= 29 +7
4x= 36
x= 9
x/3 -8 =12
x/3 = 12+ 8
x/3 = 20
x= 20(3)
x= 60
Answer:
-3 + -6= -9
because there is answer given