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4 years ago

If DH = 2x – 2 and FH = x + 6, find the value of x for which DEFG must be a parallelogram.

2 answers:

7 0

We have to find the value of x for which DEFG must be a parallelogram.
Point H is the center of the parallelogram DEFG. Therefore: DH = FH2 x - 2 = x + 62 x - 2 + 2 = x + 6 + 22 x = x + 82 x - x = x - x + 8Answer:
x = 8

yulyashka [42]4 years ago

3 0

Answer:

x=8

Step-by-step explanation:

Given that DEFG is a parallelogram.

H is the centre of the parallelogram where diagonals meet.

Since diagonals bisect each other,

DH = FH

2x-2 =x+6

Solving we get

x =8

DEFG is a parallelogram.

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Step-by-step explanation:

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3 years ago

Write 6^8 • 6^7 as a single power

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<h3>Write 6^8 • 6^7 as a single power:</h3>

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Solution:

Given that,

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3 years ago

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

Step 1: Substitute

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