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Lena [83]
3 years ago
11

Problem: A scuba diver swam 30 feet below sea level. After a couple of minutes, he went down 10 feet more. Find the total distan

ce that the scuba diver swam.​
Mathematics
1 answer:
QveST [7]3 years ago
3 0

Answer: -40 feet

Step-by-step explanation: the scuba diver starts at sea level (0) then swims down 30 feet (-30). after a couple minutes, goes down 10 feet more (-40) the scuba diver will now be -40 down from sea level. so it should be -40 because the scuba diver swam that much down.

lmk if this is incorrect, i'm not quit sure if it is or not. if i'm wrong, i'm so sorry!!

:)

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If AD/DB =AE/EC, then line segment blank is parallel to line segment blank
Marysya12 [62]

Answer:DE and BC

Step-by-step explanation:

5 0
2 years ago
Chi square Daphne likes to ski at a resort that is open from December through April. According to a sign at the resort, 20, perc
Marat540 [252]

Answer:

There is not enough evidence to suggest that the snow falls in Daphne's hometown does not follow the given distribution.

Step-by-step explanation:

The missing data for the random sample of 80 days between December and April with snowfall is:

 Month            Days

December         16

January             11

February            16

 March              18

  April                19

The Chi-square goodness of fit test would be used to determine whether the snow falls in Daphne's hometown followed the given distribution.

The hypothesis for the test can be defined as follows:

<em>H</em>₀: The snow falls in Daphne's hometown does not follow the given distribution.

<em>Hₐ</em>: The snow falls in Daphne's hometown followed the given distribution.

Assume that the significance level of the test is, <em>α</em> = 0.05.

The Chi-square test statistic is given by:

\chi^{2}=\sum\limits^{n}_{i=1}{\frac{(O_{i}-E_{i})^{2}}{E_{i}}}

The value of Chi-square test statistic is computed in the Excel sheet below.

\chi^{2}=\sum\limits^{n}_{i=1}{\frac{(O_{i}-E_{i})^{2}}{E_{i}}}=8.383

Compute the <em>p</em>-value as follows:

\text{p-value}=P(\chi^{2}_{(4)}>8.383)=CHISQ.DIST.RT(8.383,4)=0.0785

The <em>p</em>-value of the test is 0.0785.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

<em>p</em>-value = 0.0785 > <em>α</em> = 0.05.

The null hypothesis will not be rejected.

Conclusion:

There is not enough evidence to suggest that the snow falls in Daphne's hometown does not follow the given distribution.

4 0
3 years ago
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Step-by-step explanation:

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To find the domain, remember that any denominators can't be 0.

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a ≠ 0

(5/(a+1) − 3/(a−1) + 6/(a²−1)) × (a+1)/2

Distribute the a+1.

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Factor out 1/(a−1).

(5(a−1) − 3(a+1) + 6) / (2(a−1))

Simplify.

(5a − 5 − 3a − 3 + 6) / (2a−2)

(2a−2) / (2a−2)

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2 years ago
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