let's bear in mind that B is the midpoint and thus it cuts a segment into two equal halves.
![\bf \underset{\leftarrow \qquad \textit{\large 10x-6}\qquad \to }{\boxed{A}\stackrel{4x+2}{\rule[0.35em]{10em}{0.25pt}} B\stackrel{\underline{4x+2}}{\rule[0.35em]{10em}{0.25pt}\boxed{C}}} \\\\\\ AC=AB+BC\implies 10x-6=(4x+2)+(4x+2)\implies 10x-6=8x+4 \\\\\\ 2x-6=4\implies 2x=10\implies x=\cfrac{10}{2}\implies x= 5 \\\\[-0.35em] ~\dotfill\\\\ AC=(4x+2)+(4x+2)\implies AC=[4(5)+2]+[4(5)+2] \\\\\\ AC=22+22\implies AC=44](https://tex.z-dn.net/?f=%5Cbf%20%5Cunderset%7B%5Cleftarrow%20%5Cqquad%20%5Ctextit%7B%5Clarge%2010x-6%7D%5Cqquad%20%5Cto%20%7D%7B%5Cboxed%7BA%7D%5Cstackrel%7B4x%2B2%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%20B%5Cstackrel%7B%5Cunderline%7B4x%2B2%7D%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%5Cboxed%7BC%7D%7D%7D%20%5C%5C%5C%5C%5C%5C%20AC%3DAB%2BBC%5Cimplies%2010x-6%3D%284x%2B2%29%2B%284x%2B2%29%5Cimplies%2010x-6%3D8x%2B4%20%5C%5C%5C%5C%5C%5C%202x-6%3D4%5Cimplies%202x%3D10%5Cimplies%20x%3D%5Ccfrac%7B10%7D%7B2%7D%5Cimplies%20x%3D%205%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20AC%3D%284x%2B2%29%2B%284x%2B2%29%5Cimplies%20AC%3D%5B4%285%29%2B2%5D%2B%5B4%285%29%2B2%5D%20%5C%5C%5C%5C%5C%5C%20AC%3D22%2B22%5Cimplies%20AC%3D44)
Answer: Choice B) 128
Explanation:
We'll add up the given arc measures and then cut the result in half to get the angle formed by the intersecting chords (that subtend the arcs in question).
chord angle = (arc1+arc2)/2
x = (54+202)/2
x = 256/2
x = 128
Answer:
0.972222 yards
Step-by-step explanation:
35/36= 0.972222
Given that,
A population p of migrating butterflies changes over time it is represented by the equation
Where w is number of weeks.
To find,
The population after 2 weeks.
Solution,
We have,

Put w = 2 in the above equation.

So, the population after 2 weeks is 64000
.
Answer:
The worth of boat in 2013 will be $9202.6
Step-by-step explanation:
Rate of depreciation = 9% = 0.09
Cost of Boat in 2006 =$ 17,800
Cost of Boat in 2013 = ?
Years = 2013-2006= 7 years
The formula used is: 
Since the value of boat is depreciating the value of r will be r=-0.09
Here P = 17,800 , r=-0.09 and t = 7 years Finding A

So, the worth of boat in 2013 will be $9202.6