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Sav [38]
3 years ago
9

Thanks!! Can you please prove your answer! :) Thanks a lot

Mathematics
1 answer:
Tema [17]3 years ago
4 0
Divide any distance by its times. Let me do the last one.
580 divided by 10 is 58. So for 1 hour it goes 58 miles.
Answer is C
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Please help me solve this.
Vladimir [108]

Answer:

Step-by-step explanation:

i dont know man sorry

6 0
3 years ago
Read 2 more answers
50 POINTS EACH
Andrews [41]

Since s and t are complimentary, that means ∠s + ∠t = 90

From the picture, we also know that ∠t + ∠LGM = 90

Set them equal to each other:

∠s + ∠t = ∠t + ∠LGM, solve:

∠s = ∠LGM

Now using the fact that tangent = opposite/adjacent:

tan (∠s) = \frac{y}{h}

tan (∠s) = \frac{h}{x}

Set them equal to each other to get:

\frac{y}{h} = \frac{h}{x}

Solve:

h^{2}= xy\\h = \sqrt{xy}

Part B:

Using tan (∠s) = \frac{y}{h}

We get: h = \frac{3}{tan38} = 3.84 meters

Hope that helps!

3 0
3 years ago
What plus what equals negative 14
Firdavs [7]
There are a lot but when I think of it I think -14+0
8 0
4 years ago
Write an equation in slope-intercept form for the line that satisfies the following condition. slope 6, and passes through (5, 2
evablogger [386]
I can't remember if this is correct or not but I believe it would be 5 multiplied by 20 plus 6. As I said I don't Know for sure if this is correct or not. However, I hope it help
4 0
3 years ago
Read 2 more answers
Can someone help me in this question
BlackZzzverrR [31]

Answer:

The average speed of the athlete for the entire competition is approximately 21.23 km/hr

Step-by-step explanation:

The given parameters of the athlete performance in the triathlon are;

The length the athlete swims = 750 m = 0.75 km

The time the athletes spends swimming = 15 minutes = 0.25 hours

The speed with which the athlete cycles = 40 km/hr.

The time the athletes spends while cycling = 30 minutes = 0.5 hours

The distance the athlete ran = 5 km

The average speed with which the athlete ran = 3 m/s = 10.8 km/hr.

The formula for average speed, s is Average speed = Total distance/(Total time)

The distance, ∑d, the athlete covered in the entire competition is given as follows;

∑d = 0.75 km + 0.5 hr. × 40 km/hr. + 5 km = 0.75 km + 20 km + 5 km = 25.75 km

The distance, ∑t, the athlete spends in the entire competition is given as follows;

∑t = 0.25 hr. + 0.5 hr. + 5 km/(10.8 km/hr.) = 0.25 hr. + 0.5 hr. + 0.463 hr. ≈ 1.213 hr.;

Therefore;

The average speed of the athlete for the entire competition, s = ∑d/∑t = 25.75 km/(1.213 hr.) ≈ 21.23 km/hr.

6 0
3 years ago
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