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vfiekz [6]
3 years ago
10

Linda used a triple beam balance to find the mass of three identical math textbooks. If the total of the three textbooks is 654

grams, what is the mass of each textbook?
Mathematics
2 answers:
Bogdan [553]3 years ago
7 0
Each book is 218 grams
dezoksy [38]3 years ago
7 0
The answer is 218 g each.
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Solve the equation x^2-4x+85=0
lara [203]
Can't factor
use quadratic
for
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

given
1x^2-4x+85=0
a=1
b=-4
c=85

x=\frac{-(-4)+/- \sqrt{(-4)^2-4(1)(85)} }{2(1)}
x=\frac{4+/- \sqrt{16-340} }{2}
x=\frac{4+/- \sqrt{-324} }{2}
x=\frac{4+/- (\sqrt{-1})(\sqrt{324}) }{2}
remember that √-1=i
x=\frac{4+/- i(\sqrt{324}) }{2}
x=\frac{4+/- i(18) }{2}
x=2+/-9i

x=2+9i or x=2-9i
3 0
3 years ago
Identify the conclusion of the statement.
lorasvet [3.4K]

Answer:

its b

Step-by-step explanation:

5 0
2 years ago
What is 12 1/3-10 11/12
Brut [27]

Answer:

1 5/12

Step-by-step explanation:

12 1/3 - 10 11/12

We need to get a common denominator of 12

12 1/3 * 4/4 - 10 11/12

12 4/12 - 10 11/12

We need to borrow from the 12 (the whole number)  because the 2nd fraction is bigger than the first

12 becomes 11 and the 1 becomes 12/12

11+ (12/12 + 4/12) - 10 11/12

11 16/12 - 10 11/12

Subtract the whole numbers

11-10 =1

Subtract the fractions

16/12 - 11 /12  = 5 /12


We are left with 1 5/12

5 0
3 years ago
(1 point) the equation for a parabola has the form y=ax2+bx+cy=ax2+bx+c, where aa, bb, and cc are constants and a≠0a≠0. find an
Kryger [21]
A graphing calculator working the quadratic regression problem for these three points gives the equation as

y = 2x² +7x -5

5 0
3 years ago
Plz help me out with this and do show work I will be waiting.... btw u will be marked brainliest!!!!!! Fast plz
pychu [463]

Answer:

x=16°

Step-by-step explanation:

5*x-30=2*(x+18)

For the second, I'd say it is:

5*x-30=2*x+18  

Let's solve both.  

5*x-30=2*(x+18)

5x-30=2x+36

3x=66

x=22  

5*x-30=2*x+18

3x+48

x=16°

8 0
3 years ago
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