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Answer:
B. 32 square inches
Step-by-step explanation:
Each of the two triangular faces has an area of ...
A = (1/2)bh = (1//2)(6 in)(4 in) = 12 in²
The lateral surface area is the product of the prism height (0.5 in) and the perimeter of the base.
LA = (0.5 in)(5 in +5 in + 6 in) = 8 in²
So, the total area is the area of the two base and the lateral area:
SA = 2A +LA
SA = 2(12 in²) +8 in² = 32 in²
The surface area of the prism is 32 square inches.
10 to the power of 10 would be 10,000,000,000
To solve for the surface area of the pyramid, we make use
of the formula:
A= l w + l [sqrt ((w / 2)^2 + h^2)] + w [sqrt ((l / 2)^2 + h^2))
where,
l and w are the base of the pyramid = 100 mm
h is the height of the pyramid = 75 mm
Substituting the given values into the equation:
A= 100 * 100 + 100 [sqrt ((100 / 2)^2 + 75^2)] + 100 [sqrt ((100
/ 2)^2 + 75^2))
A = 10,000 + 100 (sqrt 2575) + 100 (sqrt 2575)
A = 20,148.90 mm^2
Therefore the surface area of the pyramid is about 20,149
mm^2.
Answer:
4x - 8 + 4y
Step-by-step explanation:
4(x - 2 + y)
4x - 8 + 4y
You multiply each term in the parenthesis by the number in front of it.
Double-angle formulas:
2sinФcosФ=sin(2Ф) /:2
sinФcosФ=1/2*sin(2Ф)
sin(Ф/6)cos(Ф/6)=1/2*sin(2*Ф/6)=1/2*sin(Ф/3)
cos²Ф-sin²Ф=cos(2Ф)/*7
7cos²Ф-7sin²Ф=7cos(2Ф)
7cos²(Ф/9)-7sin²(Ф/9)=7cos(2*Ф/9)=7cos(2Ф/9)
