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PilotLPTM [1.2K]
4 years ago
7

Is у=3х +5 a quadratic function

Mathematics
2 answers:
GarryVolchara [31]4 years ago
6 0

No. Its a linear function. Reason being is that x has the power of 1.

Mila [183]4 years ago
3 0

Answer:

no it is a linear equation

Step-by-step explanation:

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Given the matrices A and B shown below, solve for X in the equation -1/3X + 1/3A=B
defon

Answer:

X=[24,,-33]

Step-by-step explanation:

The given equation is :

-\frac{1}{3}X+\frac{1}{3}A=B

We multiply through by 3 to get:

X-A=-3B

Solve for x to get:

X=A-3B

The entries are: A=[-12 -3] B= [-12 10]

Let X=[a,b]

We substitute the entries to get:

[a,b]=[-12,-3]-3[-12,10]

We simplify the Right Hand Side to get:

[a,b]=[-12,-3]-[-36,30]

We simplify further to get:

[a,b]=[-12--36,-3-30]

This implies that:

[a,b]=[24,-33]

Hence, X=[24,-33]

5 0
4 years ago
Using the same coordinate plane from question 1, What is the value of n? Explain how you determined the distance between P and Q
kondor19780726 [428]

Answer:

i think its 6

Step-by-step explanation:

i dont know hope it helps

8 0
3 years ago
Please help! Which of the two companies would be more likely to release this graph to consumers?
emmasim [6.3K]

Answer:

Option B, Company B

Step-by-step explanation:

<u>Company B since they have a lot more Customer Preference</u>

<u />

Answer:  Option B, Company B

7 0
4 years ago
(3square root8x^5)-(4square root256y^3)<br> Write in exponential form<br> and simplify
lana66690 [7]

Answer:

2x^\frac{5}{3} - 4y^\frac{3}{4}

Step-by-step explanation:

Given equation:

\sqrt[3]{8x^5} - \sqrt[4]{256y^3}

((8x^5)^\frac{1}{3} - (256y^3)^\frac{1}{4} \\ (8^\frac{1}{3}  . x^\frac{5}{3} ) - (256^\frac{1}{4}. y^\frac{3}{4})\\ 2x^\frac{5}{3} - 4y^\frac{3}{4} !

6 0
4 years ago
The function f(x) has a vertical asymptote at x= [blank].
Alex73 [517]

Answer:

The vertical assymptote is at x = 0

Step-by-step explanation:

Vertical assymptote are simply defined as lines that correspond to the points where the denominator of a rational function is zero.

From the graph, we can see that the curve remains on the y - axis at x = 0

Thus, the vertical assymptote is x = 0

3 0
3 years ago
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