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3 years ago

What is this graph in vertex form?

Mathematics

1 answer:

kondor19780726 [428]3 years ago

4 0

Answer:+ 2+1

Which function in vertex form is equivalent to J (2) = x

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What is the square root of s/16 simplified

GREYUIT [131]

It will be 16[tex] 16^{2} = 256

7 0

3 years ago

Read 2 more answers

4x-5y+2x+4+6+9y+7x+2

gtnhenbr [62]

Answer:

$13x+4y+12$

Step-by-step explanation:

Combine all the like terms & then solve:

$(4x+2x+7x)+(-5y+9y)+(4+6+2)$

$13x+4y+12$

4 0

3 years ago

Read 2 more answers

Anmol got 60 marks out of 80 marks in mathematics what percent marks did he get

Kay [80]

Answer:

75%

Step-by-Step Explanation:

There are two ways to go about this.

1) We can simply put it as a fraction = 60/80.

Then since a fraction sign also means division, we divide 60 by 80 = 0.75

Then to change a decimal into a percentage, we multiply by 100% = 75%

So our answer is 75%

2) We can simply it after it is put into a fraction = 60/80 = 3/4

It should be common knowledge that 3/4 is 75% depending on what grade you are in.

But there you have it, whichever way you prefer, the answer is always 75%.

3 0

3 years ago

Try to sketch by hand the curve of intersection of the parabolic cylinder y = x2 and the top half of the ellipsoid x2 + 7y2 + 7z

vovikov84 [41]

Plug $y=x^2$ into the equation of the ellipsoid:

$x^2+7(x^2)^2+7z^2=49$

Complete the square:

$7x^4+x^2=7\left(x^4+\dfrac{x^2}7+\dfrac1{14^2}-\dfrac1{14^2}\right)=7\left(x^2+\dfrac1{14}\right)^2+\dfrac1{28}$

Then the intersection is such that

$7\left(x^2+\dfrac1{14}\right)^2+7z^2=\dfrac{1371}{28}$

$\left(x^2+\dfrac1{14}\right)^2+z^2=\dfrac{1371}{196}$

which resembles the equation of a circle, and suggests a parameterization is polar-like coordinates. Let

$x(t)^2+\dfrac1{14}=\sqrt{\dfrac{1371}{196}}\cos t\implies x(t)=\pm\sqrt{\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}}$

$y(t)=x(t)^2=\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}$

$z=\sqrt{\dfrac{1371}{196}}\sin t$

(Attached is a plot of the two surfaces and the intersection; red for the positive root $x(t)$ , blue for the negative)

4 0

4 years ago

What are the period and phase shift for f(x) = −4 tan(x − π)?

777dan777 [17]

This is the answer Period: π; phase shift: x = π

8 0

4 years ago