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3 years ago

7

Write the equation of the line that passes through the points (-6,8)(−6,8) and (8,8)(8,8). Put your answer in fully reduced poin

t-slope form, unless it is a vertical or horizontal line

1 answer:

Artemon [7]3 years ago

5 0

Answer:

y=8

Step-by-step explanation:

Point slope is y2-y1 over x2-x1

So its 8-(-6) over 8-8 which equals 14/0 which means the equation of the line is y=8

This is a horizontal line on 8 on the y axis

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Ashlee would like to buy a sweater that cost 46.90. How much tax would she pay if the tax rate is 3%?

andrezito [222]

Answer:

Tax= $1.41

Step-by-step explanation:

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3 years ago

Joe ran 3 miles yesterday and wants to run at least 12 miles this week. Write an inequality that can be used to determine the ad

ivanzaharov [21]

Answer:

3 + x >= 12

not sure what variable your using

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2 years ago

2. In the circle shown, secants PE and PF have been drawn such that mCE  82 , mDF  98 and the ratio 3. In circle O, tangent

Andrew [12]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The arc PR is $\theta _{PR} = 84$

Step-by-step explanation:

A descriptive diagram of the diagram given in the question is shown on the first uploaded image

In the circle tangent $\= {M \= Q}$ , secant $PE$ and chord $PF$ are drawn

given that $\theta _ {MPQ} = 102^o$ , $\theta _{M} = 60^o$

The objective is to determine PR

From the diagram we see that MQ is a straight which implies that the the angle

$\theta_{NPM} = 180 -102$

$\theta_{NPM} = 78^o$

Now looking at triangle NMP we see that

$\theta _{MNP} = 180 -[ \theta_{NMP} + \theta _{NPM}]$

$\theta _{MNP} = 180 - [60 + 78 ]$

$\theta _{MNP} = 42 ^o$

Now the measure of an inscribed angle is half the measure of its arc intercepted, this statement is the inscribed angle theorem

So with the knowledge

Then

$\theta_{RNP} = \frac{1}{2} \theta_{PR}$

Looking at the diagram we see that

$\theta _{MNP} = \theta_{RNP} = 42 ^o$

$42 = \frac{1}{2} \theta _{PR}$

$\theta _{PR} = 2 * 42$

$\theta _{PR} = 84$

7 0

2 years ago

Kyle boards a Ferris wheel at the 3-o'clock position and rides the Ferris wheel for multiple revolutions. The Ferris wheel rotat

SpyIntel [72]

Answer:

a) The expression for the change in angular position is $\theta = 5\cdot t$ .

b) The expression for the height of Ryan regarding the center of the Ferris wheel is $H(t) = 40\cdot \sin (5\cdot t)$ .

c) The expression for the height of Ryan above the ground is $H(t) = 40\cdot \sin (5\cdot t) + 47$ .

Step-by-step explanation:

The statement is incomplete. Complete form is introduced below:

<em>Kyle boards a Ferris wheel at the 3-o'clock position and rides the Ferris wheel for multiple revolutions. The Ferris wheel rotates at a constant angular speed of 5 radians per minute and has a radius of 40 feet. The center of the Ferris wheel is 47 feet above the ground. Let t represent the number of minutes since the Ferris wheel stated rotating.</em>

<em>a)</em><em> Write an expression (in terms of t) to represent the varying number of radians </em> $\theta$ <em> Ryan has swept out since the ride started.</em>

<em>b)</em><em> Write an expression (in terms of t) to represent Ryan's height (in feet) above the center of the Ferris wheel.</em>

<em>c)</em><em> Write an expression (in terms of t) to represent Ryan's height (in feet) above the ground. </em>

a) Let suppose that Ferris wheel rotates counterclockwise. As the Ferris wheel rotates at constant rate, this kinematic expression can be used to determine the change in angular position ( $\theta$ ), in radians:

$\theta = \omega \cdot t$ (1)

Where:

$\omega$ - Angular velocity, in radians per minute.

$t$ - Time, in second.

If we know that $\omega = 5\,\frac{rad}{min}$ , then the expression for the change in angular position is $\theta = 5\cdot t$ .

b) Geometrically speaking, Ryan's height with respect to the center of the Ferris wheel is described by the following formula:

$H(t) = r \cdot \sin (\omega\cdot t)$ (2)

Where:

$r$ - Radius of the Ferris wheel, in feet.

$H(t)$ - Height of Ryan with respect to the center of the Ferris wheel, in feet.

If we know that $\omega = 5\,\frac{rad}{min}$ and $r = 40\,ft$ , then the expression for the height of Ryan regarding the center of the Ferris wheel is $H(t) = 40\cdot \sin (5\cdot t)$ .

c) We use the following geometric expression to model Ryan's height above the ground:

$H(t) = r\cdot \sin (\omega\cdot t) +h_{o}$ (3)

Where $h_{o}$ is the height of the center of the Ferris wheel above the ground, in feet.

If we know that $h_{o} = 47\,ft$ , $\omega = 5\,\frac{rad}{min}$ and $r = 40\,ft$ , then the expression for the height of Ryan above the ground is $H(t) = 40\cdot \sin (5\cdot t) + 47$ .

5 0

3 years ago

Simplify each product. Write in standard form.

muminat

29. 2w + 13
31. 9r - 4
33. 21q + 10

6 0

3 years ago