The reflection line is located at y = -x
For point J, x is -2, so y = -(-2), which equals 2.
When it is a reflection across Y, the X values remain the same.
Find the distance of the Y point to the reflection line,
The distance from -1 to 2 is 3 units.
The new point needs to be the same distance from the reflection line.
2 + 3 units = 5.
Point J' would be (-2,5)
Answer:
1 1/5
Step-by-step explanation:
the way i solved that is because if you see how many time 20 can go into 35 which is 1 time and you have 15 left over witch make your answer 1 1/15
i hope that made scene and i hope it helped
Answer:
58.5
Step-by-step explanation:
6.5*9=58.5
3(2)-18=-12
6-18 = -12
-12 = -12
Answer:
Equation of the circle =
80 = ( x - 1)^2 + (y + 1)^2
Step-by-step explanation:
Center = (1 , -1)
Point = ( 5 , 7)
Eqn of a circle is
r^2 = (x - h)^2 + (y - k)^2
We are not given the radius of the circle, fortunately we are provided the information that the circle contains a point ( 5, 7), so we use the above information to find r
Using the center (1, -1)
h - 1
k - -1
r^2 = (x - 1)^2 + ( y - -1)^2
r^2 = (x - 1)^2 + (y + 1)^2
With the point ( 5,7)
x = 5
y = 7
r^2 = ( 5 - 1)^2 + ( 7 + 1)^2
= 4^2 + 8^2
= 16 + 64
= 80
r^2 = 80
r = square root of 80
r = 8.94
The r = 8.94 , which means the equation of the circle is
80 = (x - 1)^2 + ( y + 1)^2
