Answer: Haha I don't know the answer---Wait wait--I know the answer, its Do School and study for it and you'll find out :)
Step-by-step explanation: This is how i figured it out.... I STUDIED
Step 1
Find the area of one equilateral triangle
Applying the law of sines
in this problem
a=b=7 cm
C=60 degrees
so
cm²
Step 2
To calculate the area of the hexagon multiply the area of one equilateral triangle by 
![Area Hexagon=6*[49*\frac{\sqrt{3}}{4}] \\ Area Hexagon=73.5*\sqrt{3}](https://tex.z-dn.net/?f=%20Area%20Hexagon%3D6%2A%5B49%2A%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%5D%20%20%5C%5C%20Area%20Hexagon%3D73.5%2A%5Csqrt%7B3%7D%20%20)
cm²
therefore
the answer is the option
73.5 sqrt 3cm²
<h3>
Answer: -16n-41</h3>
Work Shown:
2(-n-3) -7(5+2n)
2(-n)+2(-3) - 7(5)-7(2n) ... distribute
-2n - 6 - 35 - 14n
(-2n-14n) + (-6-35)
-16n - 41
the number is 6 so we round up to 9.7 s
I hope that help .
