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Bingel [31]
2 years ago
14

How many liters of a 10% alcohol solution must be mixed with 40 liters of a 50% alcohol

Mathematics
1 answer:
inn [45]2 years ago
5 0

Answer:

13 \frac{1}{3}

Step-by-step explanation:

20+.1x=.4\left(40+x\right)

x=40/3 = 13 \frac{1}{3}

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Step-by-step explanation:

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$$If $A=200 \mathrm{mg}$ and $t=1000$ then,$$\begin{aligned}P &=200 e^{\left(\frac{\ln \left(1/2\right)}{1590}\right) \cdot 1000} \text \\\\&=129.33 \text { grams}\end{aligned}$$

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6 0
3 years ago
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Step-by-step explanation:

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