Answer:
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Step-by-step explanation:
Answer:
Step-by-step explanation:
The x and y intercepts occur when either x or y = 0
For the y intercept, x = 0
3(0) - 5y + 15 = 0
- 5y + 15 = 0 Subtract 15 from both sides.
-5y = - 15 Divide by - 5
-5y / -5 = - 15/-5
y = 3
For x intercept, y = 0
3x - 5(0) + 15 = 0
3x + 15 = 0 Subtract 15 from both sides
3x = - 15 Divide by 3
3x/3 = - 15/3
x = - 5
xintercept = (-5,0)
yintercept = (0,3)
Answer:
The cost of an egg is $0.11
Step-by-step explanation:
Given : The cost of one dozen of eggs is $ 1.35
We have to find the cost of one egg.
We know, one dozen has 12 units
Thus, One dozen of eggs contain 12 eggs
So cost of 12 eggs is $ 1.35
So to find the cost of one egg divide the cost by 12.
We get,
1 egg = 
Thus, The cost of an egg is $0.11
The lowest possible fraction is 3/4 because 0.75=75/100 then you divide both terms by 25 and get 3/4
Answer:
Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.
The total cost of both games is:
X + Y
We know that both games cost just above AED 80
Then:
X + Y > AED 80
From this, we want to prove that at least one of the games costed more than AED 40.
Now let's play with the possible prices of X, there are two possible cases:
X is larger than AED 40
X is equal to or smaller than AED 40.
If X is more than AED 40, then we have a game that costed more than AED 40.
If X is less than or equal to AED 40, then:
X ≥ AED 40
Now let's take the maximum value of X in this scenario, this is:
X = AED 40
Replacing this in the first inequality, we get:
X + Y > AED 80
Replacing the value of X we get:
AED 40 + Y > AED 80
Y > AED 80 - AED 40
Y > AED 40
So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.
So we proven that in all the possible cases, at least one of the two games costs more than AED 40.
