3 years ago

How many liters of a 10% alcohol solution must be mixed with 40 liters of a 50% alcohol

1 answer:

inn [45]3 years ago

5 0

Answer:

13 $\frac{1}{3}$

Step-by-step explanation:

$20+.1x=.4\left(40+x\right)$

x=40/3 = 13 $\frac{1}{3}$

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