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puteri [66]
3 years ago
13

A supervisor finds the mean number of miles that the employees in a department live from work. He finds x=29 and s=3.6 . Which s

tatement must be true?
z37 is within 1 standard deviation of the mean.
z37 is between 1 and 2 standard deviations of the mean.
z37 is between 2 and 3 standard deviations of the mean.
z37 is more than 3 standard deviations of the mean.
Mathematics
1 answer:
qwelly [4]3 years ago
3 0

Answer:

Option 3 is right

z37 is between 2 and 3 standard deviations of the mean.

Step-by-step explanation:

Let X be a random variable which represents the mean number of miles that the employees in a department live from work

X is normal (N(29,3.6)

WE have to find Z score for X

Z =\frac{x-29}{3.6}

=2.22

i.e. 37 is 2.22 std deviations from the mean.

In other words, z37 is between 2 and 3 standard deviations of the mean.

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I think that the answer is A.
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3 years ago
What is the measure of W the parallelogram shown?
nexus9112 [7]

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148 degrees

Step-by-step explanation:

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I(n,a)=\displaystyle\int\sin^nax\,\mathrm dx
For demonstration on how to tackle this sort of problem, I'll only work through the case where n is odd. We can write

\displaystyle\int\sin^nax\,\mathrm dx=\int\sin^{n-2}ax\sin^2ax\,\mathrm dx=\int\sin^{n-2}ax(1-\cos^2ax)\,\mathrm dx
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For the remaining integral, we can integrate by parts, taking

u=\sin^{n-3}ax\implies\mathrm du=a(n-3)\sin^{n-4}ax\cos ax\,\mathrm dx\mathrm dv=\sin ax\cos^2ax\,\mathrm dx\implies v=-\dfrac1{3a}\cos^3ax

\implies\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx=-\dfrac1{3a}\sin^{n-3}ax\cos^3ax+\dfrac{a(n-3)}{3a}\int\sin^{n-4}ax\cos^4ax\,\mathrm dx

For this next integral, we rewrite the integrand

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So putting everything together, we found

I(n,a)=I(n-2,a)-\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx
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Answer:2.2%

Step-by-step explanation:

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