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puteri [66]
3 years ago
13

A supervisor finds the mean number of miles that the employees in a department live from work. He finds x=29 and s=3.6 . Which s

tatement must be true?
z37 is within 1 standard deviation of the mean.
z37 is between 1 and 2 standard deviations of the mean.
z37 is between 2 and 3 standard deviations of the mean.
z37 is more than 3 standard deviations of the mean.
Mathematics
1 answer:
qwelly [4]3 years ago
3 0

Answer:

Option 3 is right

z37 is between 2 and 3 standard deviations of the mean.

Step-by-step explanation:

Let X be a random variable which represents the mean number of miles that the employees in a department live from work

X is normal (N(29,3.6)

WE have to find Z score for X

Z =\frac{x-29}{3.6}

=2.22

i.e. 37 is 2.22 std deviations from the mean.

In other words, z37 is between 2 and 3 standard deviations of the mean.

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We know

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\\ \sf\longmapsto L=\dfrac{27}{72}\times 14π

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6 0
3 years ago
Write a formula that will yield the nth term of the sequence: 3,-2,-7,-12
RUDIKE [14]

Answer:

-5n + 8

Step-by-step explanation:

<u>1. What is the difference?</u>

  The sequence goes down by 5. This means that the formula will have -5n in it.

<u>2. Work out the term before the first term.</u>

    The first term is 3, and we know that the sequence goes up by 5. So, to get the term before 3 we would add 5.

3 + 5 = 8   Remember, this is positive 8. (+8)

<u>3. Put that term at the end of the equation. </u>

   We have -5n already and we just worked out the term before the first one which is positive 8 - so put that at the end of the equation.

-5n + 8  This is our answer!

Just to prove it works:

<em>Substitute:   n = term</em>

Lets see if we can get the 3rd term which is -7. (n = 3)

-5(3) + 8

-15 + 8 = -7

See, it works!

8 0
3 years ago
What percent of the first 20 natural numbers are prime numbers?
Brilliant_brown [7]
The primes are 2, 3, 5, 7, 11, 13, 17, 19. There are 8 of them, so they make up 40% of the numbers 1–20.
3 0
3 years ago
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3x-15=1+7x
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Answer:

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3 years ago
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