Answer:
Looks like a toy for the kids and the kids are doing well 6 I have been doing a lot of work on the graph of my own and my
By hit and trial of each option and also by graph, solutions to f(x) = 3ˣ and g(x)=2x-1 will be 0 and 1.
given functions are,
let us put x=0
f(0) = 1
g(0) = 1
f(0)=g(0)=1
so 0 will be a solution.
let us put x=1
f(1)= 3
g(1) = 3
f(1)=g(1)=3
so 1 will be also a solution
let us put x=2
f(2) = 9
g(2) = 5
f(2)≠g(2)
so 2 will not be solution.
x=-2 and x=-1 clearly will not be solution because,
g(-2) = negative value but f(x) cannot be negative, being an exponential function.
<h3>
what is an exponential function?</h3>
Any function in form f(x)= pˣ, where p≥1, is called an exponential function.
therefore, solutions to f(x) = g(x) will be 0 and 1.
to get more about exponential function refer to:
brainly.com/question/2456547
Your answer for that is b i think
Answer:
x = 2 + sqrt(2) or x = 2 - sqrt(2) thus B. is your answer
Step-by-step explanation:
Solve for x over the real numbers:
4 x^2 - 16 x + 8 = 0
Hint: | Write the quadratic equation in standard form.
Divide both sides by 4:
x^2 - 4 x + 2 = 0
Hint: | Solve the quadratic equation by completing the square.
Subtract 2 from both sides:
x^2 - 4 x = -2
Hint: | Take one half of the coefficient of x and square it, then add it to both sides.
Add 4 to both sides:
x^2 - 4 x + 4 = 2
Hint: | Factor the left-hand side.
Write the left-hand side as a square:
(x - 2)^2 = 2
Hint: | Eliminate the exponent on the left-hand side.
Take the square root of both sides:
x - 2 = sqrt(2) or x - 2 = -sqrt(2)
Hint: | Look at the first equation: Solve for x.
Add 2 to both sides:
x = 2 + sqrt(2) or x - 2 = -sqrt(2)
Hint: | Look at the second equation: Solve for x.
Add 2 to both sides:
Answer: x = 2 + sqrt(2) or x = 2 - sqrt(2)
Answer:The expression is 6y - 4x
Step-by-step explanation: