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zhannawk [14.2K]
3 years ago
5

If v is one-third of the quantity 3 less than u, how does v change if u is increasing?

Mathematics
1 answer:
kykrilka [37]3 years ago
3 0

Answer:

v increases when u increases

Step-by-step explanation:

From the question, we have that

v = u - \frac{1}{3} * 3

v = u - \frac{3}{3}

v = u - 1

Take u = 1

v = u - 1

v = 1 - 1

v = 0

Take u = 2

v = u - 1

v = 2 - 1

v = 1

Take u = 10

v = u - 1

v = 10 - 1

v = 9

<em>This implies that an increment in u brings an increment in v</em>

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Olenka [21]

The number of pennies is an illustration of pattern and sequence.

The number of pennies in the nth square is 2^{n-1

From the complete question, we have the following parameters

f(1) =1

f(2) =2

f(3) =4

f(4) =8

Rewrite the functions as follows:

f(1) = 2^0

f(2) = 2^1

f(3) = 2^2

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Express 3 as 4 - 1

f(4) = 2^{4-1

Replace 4 with n

f(n) = 2^{n-1

Hence, the number of pennies in the nth square is 2^{n-1

Read more about pattern and sequence at:

brainly.com/question/24655254

4 0
3 years ago
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olganol [36]

Answer:

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Step-by-step explanation:

4 is the highest number that fits into all terms of the expression :

So outside the bracket will be 4x :

To find what is inside the bracket we divide each term by 4x  

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Answer:

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Step-by-step explanation:

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