3 years ago

If you roll a fair six sided dies and a four sided dies what is the probability that neither dies shows a one

Mathematics

1 answer:

miv72 [106K]3 years ago

8 0

If you roll a fair six sided dies and a four sided dies, the probability that neither dies shows a one is 8/10 -4/5.

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(3 -/ 5) power 10 divided (3 -/ 5) power 8<br><br><br> simplify and express in exponential form

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√
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3 years ago

Choose the true statement about the graph of x - 1 ≤ 2.. open circle on 1 and all numbers to the right shaded. closed circle on

AnnyKZ [126]

X - 1 < = 2....add 1 to both sides
x < = 2 + 1
x < = 3

This will have a closed circle (because there is an equal sign in the problem)...on 3, and all numbers to the left are shaded(because it is less then).

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3 years ago

Read 2 more answers

Emma has 56 37⁄40 bags of dog food to feed all of the dogs at the animal shelter. The dogs each eat 81⁄4 bags of food per week.

deff fn [24]

$\text{Answer: Number of weeks }=56$

Explanation:

Since we have given that

$\text{Number of bags of dog food to feed all of the dogs at the animal shelter} =56\frac{37}{40}$ $\text{Number of bags of food per week eaten by dogs }= 8\frac{1}{4}$

So,

$\text{Number of weeks worth of dog food Emma have } =\frac{56\frac{37}{40}}{8\frac{1}{4}}$

$\text{Number of weeks worth of dog food Emma have }=\frac{2240\times 4}{40\times 4}\\\text{Number of weeks worth of dog food Emma have }=\frac{2240}{40}\\\text{Number of weeks worth of dog food Emma have }=56$