All categories

3 years ago

Change 3 4/9 in to a decimal

Mathematics

1 answer:

o-na [289]3 years ago

8 0

Hey there,

Answer:

3 4 / 9 = 3.444444444444
= 3.4

Hope this helps :D

~Top♥

You might be interested in

Which choice is equivalent to the fraction below when x is an appropriate value? Hint: Rationalize the denominator and simplify.

densk [106]

$\frac{3}{3- \sqrt{6x} } = \frac{3}{3- \sqrt{6x} } \times \frac{3+ \sqrt{6x} }{3+ \sqrt{6x} } \\ = \frac{3(3+ \sqrt{6x})}{3^2-( \sqrt{6x} )^2} = \frac{3(3+ \sqrt{6x})}{9-6x} \\ =\frac{3(3+ \sqrt{6x})}{3(3-2x)}=\frac{3+ \sqrt{6x}}{3-2x}$

6 0

3 years ago

Read 2 more answers

write the equation for an exponential function, in the forms y = a x b^x, whose graph passes through the coordinate points (1, 7

zysi [14]

Y = abˣ
(a ≠ 0, b ≠ 0)

(1, 7.5)
x = 1
y = 7.5
  ↓
7.5 = ab

(3, 16.875)
x = 3
y = 16.875
  ↓
16.875 = ab³

7.5 = ab
b b
7.5/b = a

  16.875 = ab³
b³ b³
16.875/b³ = a

7.5/b = 16.875/b³
7.5/b(b³) = 16.875/b³(b³)
7.5b² = 16.875
7.5 7.5
b² = 2.25
  √(b²) = √(2.25)
b = 1.5

a = 7.5/b
a = 7.5/1.5
a = 5

y = 5(1.5)ˣ

8 0

4 years ago

Read 2 more answers

What is 2 gallons minus 5 quarts

MariettaO [177]

There are 4 quarts in a gallon.
In two gallons would be 8 quarts.

2 gallons - 5 quarts = 8 quarts - 5 quarts = 3 quarts.

Note: 3 quarts is 3/4 or .75 of a gallon.

6 0

4 years ago

Find the domain and range of f(x). Please explain your answer. f(x) = √(x^2+5x+6)

timama [110]

Answer:

Domain:— [ x ≥ -2, x ≤ -3 ]

Range:— [ y ≥ 0 ]

Step-by-step explanation:

You may use graphing calculator to draw a graph and examine the graph’s domain and range. However, I’ll explain further about the graph of quadratic in a surd.

First, factor the quadratic expression in the surd:—

$\displaystyle \large{f(x)=\sqrt{(x+3)(x+2)}}$

We can find the x-intercepts by letting f(x) = 0.

I’ll be separating in two parts — one for finding x-intercept and one for finding y-intercept.

__________________________________________________________

Finding x-intercepts

Let f(x) = 0.

$\displaystyle \large{0=\sqrt{(x+3)(x+2)}}$

Solve for x, square both sides:—

$\displaystyle \large{0^2 = (\sqrt{(x+3)(x+2)})^2}\\\displaystyle \large{0=(x+3)(x+2)}$

Simply solve a quadratic equation:—

$\displaystyle \large{x=-3,-2}$

Therefore, x-intercepts are:—

$\displaystyle \large{\boxed{x=-3,-2}}$

__________________________________________________________

Finding y-intercept

Let x = 0.

$\displaystyle \large{f(x)=\sqrt{(0+3)(0+2)}}\\\displaystyle \large{f(x)=\sqrt{3 \cdot 2}}\\\displaystyle \large{f(x)=\sqrt{6}}$

Therefore, y-intercept is:—

$\displaystyle \large{\boxed{\sqrt{6}}}$

__________________________________________________________

However, I want you to focus on x-intercepts instead. We know that the square root only gives you a positive value. That means the range of function can only be y ≥ 0.

For domain, first, we have to know how or what the graph looks like. You can input the function in a graphing calculator as you’ll see that when x ≥ -2, the graph heads to the right while/when x ≤ -3, the graph heads to the left. This means that the lesser value of x-intercept gets left and more value get right.

See, between -3 < x < -2, there is no curve, point or anything between the interval. Therefore, -3 < x < -2 does not exist in function.

Hence, the domain is:—

x ≥ -2, x ≤ -3