7 tenths
6 hundredths answer
9 thousandths
Answer:
If y(t) is the mass (in mg) remaining after t years, then y(t) = y(0) (0.5)^{t/T} = 400 (0.5)^{t /4}, where T is the half-life period and y(0) is the amount at t = 0 years (initial).
Then at t = 20:
y(20) = 400 (0.5)^{20 /4} = \text{12.5 mg}
Step-by-step explanation:
1 Simplify 1.32−0.241.32-0.241.32−0.24 to 1.081.081.08
17.281.08×0.6\frac{17.28}{1.08}\times 0.6
1.08
17.28
×0.6
2 Simplify 17.281.08\frac{17.28}{1.08}
1.08
17.28
to 161616
16×0.616\times 0.616×0.6
3 Simplify
9.69.69.6
Answer:
X=6.833-0.66y
Y=10.25-1.5x
Step-by-step explanation:
Make each the subject
