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2 years ago

Is WXY ~ ZYV? Justify your answer. The image is not drawn to scale.

Mathematics

2 answers:

Nataliya [291]2 years ago

8 0

I hope this helps you

lana [24]2 years ago

4 0

Answer: C. Yes, WXY ~ ZYV with a scale factor of 9:8.

Step-by-step explanation:

In the given picture, we have two triangles Δ WXY and Δ ZYV in which

$\angle {X}=\angle{Y}$ [Right angle]

$\angle {W}=\angle{Z}$

Therefore, by AA- similarity postulate, we have

$\triangle{WXY}\sim\triangle{ZYV}$

The scale factor is given by :-

$k=\dfrac{WX}{ZY}=\dfrac{XY}{YV}=\dfrac{WY]{ZV}$

$\Rightarrow k=\dfrac{18}{16}=\dfrac{6.75}{6}=\dfrac{22.5}{20}=\dfrac{9}{8}$

Hence, $\triangle{WXY}\sim\triangle{ZYV}$ with scale factor of 9:8 .

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vampirchik [111]

Answer:

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Step-by-step explanation:

2x-3y = -5 --------- (1)

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2 years ago

Lim x--> 0 (e^x(sinx)(tax))/x^2

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Make use of the known limit,

$\displaystyle\lim_{x\to0}\frac{\sin x}x=1$

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3 years ago

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Karo-lina-s [1.5K]

12 girls for every 5 boys
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3 years ago

Read 2 more answers

Its pretty easy if you are good at math! Please help!

aleksley [76]

Step-by-step explanation:

Explanation:

The trick is to know about the basic idea of sequences and series and also knowing how i cycles.

The powers of i will result in either: i, −1, −i, or 1.

We can regroup i+i2+i3+⋯+i258+i259 into these categories.

We know that i=i5=i9 and so on. The same goes for the other powers of i.

So:

i+i2+i3+⋯+i258+i259

=(i+i5+⋯+i257)+(i2+i6+⋯+i258)+(i3+i7+⋯+i259)+(i4+i8+⋯+i256)

We know that within each of these groups, every term is the same, so we are just counting how much of these are repeating.

=65(i)+65(i2)+65(i3)+64(i4)

From here on out, it's pretty simple. You just evaluate the expression:

=65(i)+65(−1)+65(−i)+64(1)

=65i−65−65i+64

=−65+64

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So,

i+i2+i3+⋯+i258+i259=-1

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3 years ago

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Anna71 [15]

Answer:

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3 years ago