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Romashka-Z-Leto [24]
3 years ago
8

What is the equation for a parabola with a focus at (-2,5) and a directrix at x=3

Mathematics
2 answers:
Gre4nikov [31]3 years ago
4 0
4 is the answer hope this helps  :   )
Kitty [74]3 years ago
4 0
4 is the correct answer
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Can somebody help me please​
serious [3.7K]

Answer: y-int ( 0, 0.4 )      x-int ( 0.3, 0 )

Step-by-step explanation:

Given in the graph

X axis and Y axis.

5 0
3 years ago
Read 2 more answers
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
15 points and crown <br> solve by factoring (x+6)(2x-5)=0<br> I am confused
Reika [66]
Remember, in order for this equation to be true either one of the polynomials has to equal 0
So:

-> x+6 = 0

x=-6


-> 2x-5 = 0

2x= 5

x= 5/2


So the answer is x=-6 and x= 5/2.


Hope this helps!
7 0
4 years ago
What is the volume of the pyramid in the diagram?
Jlenok [28]
The volume of a pyramid is lwh/3
4 0
3 years ago
Help asap please bbbbb
Alex

Answer:432 whats the other option 4300

Step-by-step explanation:

4 0
2 years ago
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