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3 years ago

Grandma's trash, no earnings, boxed like a fish, 200 pumped, absolutely destroyed

Mathematics

1 answer:

jenyasd209 [6]3 years ago

6 0

Get dog on, look at ur hitbox, ur as free as a public restroom,

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The South Coast Air Basin (Los Angeles, Orange, and San Bernardino counties) does not meet the air quality standards for carbon

Archy [21]

Answer:

0.2225 gr/mile

Step-by-step explanation:

Let's work out first the amount of CO sent out in 1990.

The population we estimated in 12.5 million people with a total of driven miles per year of about

12.5 million*8,700 = 108,750 million miles.

With an CO emission factor of 0.9 g per mile, we would have a total of CO emitted rounding 0.9*180,750 = 97,875 million grams

Now, we must estimate the population for 2020.

Since we are assuming an exponential growth, the population in year t is given by a function

$\bf P(t)= Ce^{kt}$

where C and k are constants to be determined.

We can take 1980 as year 0. This way calculations are lighter. 1990 is year 10 and 2020 is year 20.

So P(0) = 10.3 and C=10.3

So far we have

$\bf P(t)= 10.3e^{kt}$

Given that P(10)=12.5

$\bf 10.3e^{k*10}=12.5\rightarrow e^{10k}=\frac{12.5}{10.3}=1.21359\rightarrow \\10k=log(1.21359)\rightarrow k=0.01936$

And the function that models the population growth is

$\bf P(t)= 10.3e^{0.01936t}$

We need P(20)

$\bf P(20)= 10.3e^{0.01936*20}=10.3e^{0.38717}=15.17\;million$

If the miles driven per person per year remains constant at 8700 mi/yr.person, then we have a total miles driven of

15.17*8,700=131,979 million miles, so the CO emitted would be 0.9*131,979=118,781.1 million grams.

The 30% of the CO sent out in 1990 is 0.3*97,875=29,362.5 million grams.

We must reduce 118,781.1 down to 29,362.5

Hence the new CO emission factor would be

29,362.5/131,979 = 0.2225 gr/mile

6 0

3 years ago

Can someone please help me with this

oee [108]

Answer:

165 pennies

Step-by-step explanation:

250/1.52=164.473684211, but just round it to the nearest whole number whitch would be 165!

6 0

2 years ago

A pump fills a pool at the rate of 20 cubic meters in an hour. If each cubic meter of water costs $10, how many minutes will the

fomenos

The first thing any good mathematician does is convert the measurements to the same unit as what the question is asking. In this problem, it states that the pool fills at a rate of 20 cubic meters per hour. Just keep in mind that an hour is 60 minutes.

The next step is to see how many cubic meters will cost $300. This can be done by dividing 300 by 10. This gets you 30 cubic meters of water.

You already know that 60 minutes is 20 cubic meters of water. That leaves the remaining 10 cubic meters of water. By dividing the rate given, you get that 30 minutes is 10 cubic meters of water. Add the 60 and 30 together to get 90 minutes.

It will take 90 minutes for the pump to use $300.

7 0

3 years ago

Someone please help me I’ll give out brainliest please dont answer if you don’t know

sasho [114]

Answer:

$56.25

Step-by-step explanation:

3% of 750, then multiply by 2.5

6 0

3 years ago

under which of the following operations are the polynomials 8a 14 and 3b - 9 not closed? a. subtraction b. multiplication c. add

Alex787 [66]

<span>I think it's a. subtraction.</span>

8 0

3 years ago