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Drupady [299]
3 years ago
8

HElP pLeAsE 32y + 12y = 44y

Mathematics
1 answer:
BartSMP [9]3 years ago
3 0

Answer:44y=44y

Step-by-step explanation: combine the like terms of 32y and 12y and u get 44y=44y which cant be simplified further

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A NASA mathematician used a system of equations to determine the point in space where a satellite crossed paths with a massive p
nikitadnepr [17]

Answer:

Option D.

3 equations with 3 variables

Step-by-step explanation:

The coordinates of a point in space must necessarily have 3 components. One to describe the distance on the x axis, another to describe the distance on the y axis to the point, and a third to describe the distance on the z axis.

If we have three variables, then 3 equations are needed to solve the system. With less than 3 equations it would be impossible to solver the system.

Therefore the correct answer is option D.

3 equations with 3 variables

8 0
3 years ago
4 / 7 * 2 / 3 * *9/16
lara31 [8.8K]

\bf \cfrac{4}{7}\cdot \cfrac{2}{3}\cdot \cfrac{9}{16}\implies \cfrac{4}{16}\cdot \cfrac{9}{3}\cdot \cfrac{2}{7}\implies \cfrac{1}{4}\cdot \cfrac{3}{1}\cdot \cfrac{2}{7}\implies \cfrac{1}{7}\cdot \cfrac{3}{1}\cdot \cfrac{2}{4}\implies \cfrac{1}{7}\cdot \cfrac{3}{1}\cdot \cfrac{1}{2}\\\\\\\cfrac{1\cdot 3\cdot 1}{7\cdot 1\cdot 2}\implies \cfrac{3}{14}

4 0
3 years ago
Please help me out . :)
Veseljchak [2.6K]

Answer:

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5 0
3 years ago
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Which rigid transformation(s) would map ΔJKL onto ΔPQR? a reflection only a rotation only a rotation and a reflection a translat
solniwko [45]

Step-by-step explanation:

A rigid transnformation is also know as isometrie. <u>This are transformations of the plane that preserves the lengths</u>. There are 3 types of isometries and each one can be combined with the others.

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  • Translation (second figure)
  • Rotation (third figure)

Combining this transformations you will be able to transform ΔJKL onto ΔPQR

6 0
3 years ago
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Which point lies on a circle with a radius of 5 units and center at P(6, 1)?
guapka [62]

Answer:

B.

R (2,4)

soln

center(h,k)=(6,1)

radius (r)=5units

so

eqn of circle is (x-6)^2+(y-1)^2=5^2

2 2

or, 25=x +y -12x-2y+36+1 now , only the given point (6,1)satisfies the eqn so this point lies on circle

3 0
3 years ago
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