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vova2212 [387]
3 years ago
6

What is 8x+9x simplified completely

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
8 0

Answer:

17x

Step-by-step explanation:

Zigmanuir [339]3 years ago
7 0
17x
Add coefficients
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If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen
Alisiya [41]
The answer is <span>2(–4y + 13) – 3y = –29

Step 1: Express </span><span>x from the second equation
Step 2: Substitute x into the first equation:

The system of equations is:
</span><span>2x – 3y = –29 
x + 4y = 13

Step 1: 
</span>The second equation is:    x + 4y = 13
Rearrange it to get x:         x = - 4y + 13

Step 2:
The first equation is:          2x – 3y = –29 
The second equation is:    x = - 4y + 13
Substitute x from the second equation into the first one:
2(-4y + 13) - 3y = -29

Therefore, the second choice is correct.
5 0
4 years ago
Anyone know how to do the elimination method? pls help asap
givi [52]
Hey there!

Check out image!


Answer is (-7,5)

6 0
2 years ago
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What is the answer to r - 4.5 &lt; 11
Cloud [144]
R - 4.5 < 11
—
r would be 15.5
[ r = 15.5 ]
5 0
2 years ago
Verify if f(x)= 5-3x/2 and g(x)= 5-2x/3 are inverses. Please show step by step.
mestny [16]

Since f(g(x)) = g(f(x)) = x, hence the function f(x) and g(x) are inverses of each other.

<h3>Inverse of functions</h3>

In order to determine if the function f(x) and g(x) are inverses of each other, the composite function f(g(x)) = g(f(x))

Given the function

f(x)= 5-3x/2 and

g(x)= 5-2x/3

f(g(x)) = f(5-2x/3)

Substitute

f(g(x)) = 5-3(5-2x)/3)/2

f(g(x)) = (5-5+2x)/2

f(g(x)) = 2x/2

f(g(x)) = x

Similarly

g(f(x)) = 5-2(5-3x/2)/3

g(f(x)) = 5-5+3x/3

g(f(x)) = 3x/3

g(f(x)) =x

Since f(g(x)) = g(f(x)) = x, hence the function f(x) and g(x) are inverses of each other.

Learn more on inverse of a function here: brainly.com/question/19859934

#SPJ1

7 0
1 year ago
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)
vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

x^{\frac{2}{3}}+y^{\frac{2}{3}}=4

We have to find the equation of tangent line to the given curve at point (-3\sqrt3,1)

By using implicit differentiation, differentiate w.r.t x

\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0

Using formula :\frac{dx^n}{dx}=nx^{n-1}

\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}

\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}

\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}

Substitute the value x=-3\sqrt3,y=1

Then, we get

\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}

\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}

Slope of tangent=m=\frac{1}{\sqrt3}

Equation of tangent line with slope m and passing through the point (x_1,y_1) is given by

y-y_1=m(x-x_1)

Substitute the values then we get

The equation of tangent line is given by

y-1=\frac{1}{\sqrt3}(x+3\sqrt3)

y-1=\frac{x}{\sqrt3}+3

y=\frac{x}{\sqrt3}+3+1

y=\frac{x}{\sqrt3}+4

This is required equation of tangent line to the given curve at given point.

8 0
3 years ago
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