Question

Jorge is comparing two data sets. He uses the mean and mean absolute deviation to compare the center and variability of the data sets. If the measures of center and variability accurately describe the sets, which best describes both data sets?
a
symmetrical and containing outliers
b
not symmetrical without outliers
c
symmetrical without outliers
d
not symmetrical or containing outliers

Answer 1

Answer:

The correct option is;

c. Symmetrical without outliers

Step-by-step explanation:

Here we have the measure of central tendency given as follows

Mean, μ = Σx/n

Mean absolute deviation, $\frac{\sum \left | x -\mu \right |}{n}$

Therefore, where both measures of central tendency and variability accurately describes the data then

For the mean, Σx/n to describe the data, it must be without outliers

For the mean absolute deviation,  $\frac{\sum \left | x -\mu \right |}{n}$, to describe the data it must be symmetrical.