This has a vertex at (1,-5) and otherwise looks like y=x^2; the two points one x unit away from the vertex are also 1 y unit away, the two points two away are 4 units higher, etc.
That's in vertex form. We're not shown any choices; let's multiply this out.
Either one of those.
Answer:
A slope of -3 and a y-intercept of 4
Step-by-step explanation:
In y = -3x + 4, -3 is negative, meaning that the line faces down. 4 is positive and is the y-intercept, meaning that it is 4 points above the origin (0, 0). -3 also means that for every 1 point that the x coordinate is moved, the line will go down 3 points. For example, (1, 3) is on the line and so is (2, 6).
Answer:
x^2 + 7x - 3 = 0
Step-by-step explanation:
I think you meant "width of the frame" from outside of frame to outside of mirror.
Let x represent the width of the frame.
Area of mirror is (3 ft)(4 ft) = 12 ft^2. Total area of mirror and frame is 15 ft^2. The 3 ft^2 difference is the area of the frame.
But you were asked to find a quadratic equation that would give you the "width" of the frame.
The "new" width would be 3 + x and the "new" height would be 4 + x.
Then the area of the mirror and frame together would be
A = (3 + x)(4 + x) = 15 ft^2, or
12 + 7x + x^2 = 15 ft^2, or
x^2 + 7x - 3 = 0. This is the desired quadratic equation.
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