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IrinaK [193]
3 years ago
11

Help on number 2 please

Mathematics
1 answer:
Katarina [22]3 years ago
3 0

Answer:

y=12.73 x=9

Step-by-step explanation:

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Which expression best represents all solutions of x for the equation cot x = –1.25, where k is any integer?
Alika [10]

Answer:

The answer is "-0.675+ k \ \pi"

Step-by-step explanation:

Given:

\to \cot \ x = - 1.25\\\\\to \cot \ x =  \cot (-0.675)\\\\\to x=  k \pi + (-0.675)\\\\\boxed{\boxed{\boxed{x=  -0.675 + k \pi}}}

5 0
3 years ago
Ms. Monet gave 2 1/2 cups of red paint to each of her 20 students. How many quarts
kodGreya [7K]
12.5 Quarts


Explanation:

It takes 4 cups to make a quart so 2.5 would equal 0.625 quart

Then you would take 0.625 x 20 which would then equal 12.5 Quarts
6 0
2 years ago
PLEASE HELP!! BRAINLIEST ANSWER AND FASTEST ANSWER GETS TON OF FREE POINTS...MATH WHIZZES, HELP ME OUT. FORGOT HOW TO DO THIS.
Julli [10]
Inscribed angles equal half of their arc length. So <D+ <B = 180
substitute: x+24+x+10 = 180 
solve: 2x + 34 = 180
2x= 146
x= 73
NOw find the measure of angle A:
<a = x + 15
<a = 73 + 15
<a = 88
 Now to find <C
<C = 180- 88
<C = 92
Hope this helps!
5 0
2 years ago
Divide 5 in a ratio of 1:2:3
anastassius [24]
In plain and short, we simply divide 5 by (1+2+3) and then distribute the pieces likewise

\bf 5\qquad 1:2:3\qquad \cfrac{5}{1+2+3}\implies \cfrac{5}{6}&#10;\\\\\\&#10;\stackrel{\textit{ratio of 1}}{1\left( \frac{5}{6} \right)}\qquad \stackrel{\textit{ratio of 2}}{2\left( \frac{5}{6} \right)}\qquad \stackrel{\textit{ratio of 3}}{3\left( \frac{5}{6} \right)}\qquad \implies \qquad \frac{5}{6}~:~\frac{5}{3}~:~\frac{5}{2}

add the ratios up, and you'll get 5.
4 0
2 years ago
Tony operates a skate rental company. He charges an equipment fee of $3 plus $6 per hour. Which equation represents this linear
slava [35]

Answer: A) y = 6x +3

Step-by-step explanation:

Let x represent the number of hours. $6 per hour can now be written as 6x.

Now, we must account for the $3 flat, fee and add it to 6x, getting 6x + 3

6 0
2 years ago
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