There were 11 crackers to begin with. Because if you give the fractions a common denominator of 12 you multiply how you got to 12 by the top as well then you would subtract and add it to the five that were left
Answer:
Step-by-step explanation:
area of a trapezoid: a= a+b/2 H
so...
5x+7+x+3/2=6x+10/2=3x+5
then take 3x+5 and multiply it by 2x-1
soo... (3x+5)(2x-1) and I used FOIL
so then 6x^2-3x+10x-5
which is equal to 6x^2+7x-5
I hope this helps =)
When one side of a quadrilateral is not to be fenced (ex. a river, as in this case), the optimal fencing to maximize the area is always to use half the fencing for the length, and one-fourth for each of the two widths
A) For 1000 ft of fencing which is to be used to cover 1 length and 2 widths:
L = 1000/2 = 500, and W = 1000/4 = 250. The optimal dimensions will be 250 x 500 ft.
B) This will result in an area of 250*500 = 125,000 sq. ft.
When the last digit end in 0 every time
Example: 100,110,120,130
The answer has to be 2 I think