The sum of three consecutive integers is three times the middle one: if we call the middle one , the three numbers are
So, their sum is
Which is three times the middle one.
So, if the sum of three consecutive intergers is 48, the middle one must be 48/3 = 16.
So, the three numbers are 15, 16 and 17
Answer:
See attachment
Step-by-step explanation:
First solve this like a normal equation:
-3x - 6 > 9
Add 6 to both sides:
-3x > 9 + 6
-3x > 15
Divide by -3 and remember to switch the inequality sign:
x < 15/(-3)
x < -5
Think about the graph of x = -5. It's a vertical line crossing the y-axis at x = -5. Now, we have x is less than -5. That means all the values less than -5 should be viable solutions. So, shade the part of the graph to the left of the vertical line.
Also, since we have x < -5 and not x ≤ -5, the line should be dotted.
See graph attached.
<em>~ an aesthetics lover</em>
