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emmainna [20.7K]

3 years ago

5

What is the area of the trapezoid. 21m, 7m, 21m.

1 answer:

kolbaska11 [484]3 years ago

7 0

Answer:

249m

Step-by-step explanation:

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Write a recursive definition for the sequence 14, 10, 6, 2...

VladimirAG [237]

The general form of recursive definition for arithmetic sequence:
$a_{n}=a_{1}+d(n-1)$

So, what we need to do is to find $a_{1}$ and $d$ .
$a_{1}=14$
$d=a_{2}-a_{1}=10-14=-4$
Having found these two values we can now define our recursive sequence:
$a_{n}=14-4(n-1)$
$a_{n}=14-4n+4$
$a_{n}=18-4n$

7 0

3 years ago

Read 2 more answers

examples of subtraction of two fractions ( between 0-1) with a common denominator. IN STEPS ALL WORK, I need two examples.

kykrilka [37]

Answer:

Step-by-step explanation:

3/5 - 2/5 = (3-2)/5 = 1/5

7/10 - 3/10 = (7-3)/10 = 4/10 = 2/5

3 0

2 years ago

2. Suppose (220)_b and (251)_b are the squares of consecutive integers. Determine b.

Andrei [34K]

Let $x$ and $x+1$ be these consecutive integers. For some base $b$ , we can write

$(x_{10})^2=220_b=2b^2+2b$

$((x+1)_{10})^2=251_b=2b^2+5b+1$

If

$x^2=2b^2+2b$

then

$x^2+1=2b^2+2b+1$

Now,

$x^2+2x+1=2b^2+5b+1$

$2x+2b^2+2b+1=2b^2+5b+1$

$\implies2x=3b$

Squaring both sides gives

$4x^2=9b^2$

and so

$4(2b^2+2b)=9b^2$

$\implies8b^2+8b=9b^2$

$\implies b^2-8b=0\implies\boxed{b=8}$

(because the base has to be non-zero)

3 0

3 years ago

Please zoom in before you start solving because there are tricks in here. What is the answer?Please actually look at the picture

Annette [7]

Answer:

I think 109 is the answer

5 0

3 years ago

Read 2 more answers

Consider the image of EFGH for the translation (x, y) → (x – 3, y + 1). What is the ordered pair of F′?

omeli [17]

Answer:

$F'(-1,3)$

Step-by-step explanation:

The rule for the translation is given as

$(x,y)\rightarrow (x-3,y+1)$

The coordinates of F are (2,2).

We substitute these coordinates into the translation rule to find the coordinates of F'.

$F(2,2)\rightarrow F'(2-3,2+1)$

$F(2,2)\rightarrow F'(-1,3)$

3 0

3 years ago