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SVEN [57.7K]
2 years ago
14

Which of the following system of linear inequalities is represented by the solution graphed below

Mathematics
2 answers:
e-lub [12.9K]2 years ago
8 0

Answer:

C. y≥d2 and y≤x

Step-by-step explanation:

First of all, we have to look at the shaded part of the graph.

The red line is a continuous line which means we also take the number that the line crosses, and the blue line is a dotted line which means the value gets close to the number but it never touches it.

If we write equations for both lines, just to draw the lines not to draw the shaded area, we can see that the equation for the red line would be <em>y=2 </em>and that the equation for the blue line would be <em>y=x.</em>

To write the lines we just have to substitute the values of y that we get, in the first equation we will always get <em>y=2</em> so it will be a horizontal line in 2, and the second line we substitute values of x and they will be the same values for y.

Now we look at the shaded area, first of all the shaded area is over and not under the red line so we can assume that <em>y>2</em>, but because we have a continuous line we know it can also take 2 as a value so it will be y≥ 2 (y is greater or equal to 2).

Now in the blue line, with the equation y=x, the shaded area is under it and not over. This means y<x (y is less than x), and in this case, we have a blue dotted line which means y can´t take values of the blue line, only smaller values.

So we get as an answer:

y≥2 and y<x, and that will be the shaded area.

12345 [234]2 years ago
5 0

Answer:

C

Step-by-step explanation:

The wanted region(shaded part)..is greater or equal to 2 due to the bold line...so hence the first inequality is....y is greater than or equal to 2

And the second solution....is y is less than x because of the continuous broken line...hence it cant be less than or equal to

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Answer:

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Step-by-step explanation:

To calculate the product, we need to multiply each member of each multiplier:

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\bold{\huge{\purple{\underline{ Solutions }}}}

<h3><u>Solution </u><u>(</u><u>a)</u><u> </u><u>:</u><u>-</u></h3>

\bold{\dfrac{ 7}{6}}{\bold{ + }}{\bold{\dfrac{ 2}{5}}}

  • <u>By </u><u>taking </u><u>LCM </u><u>of </u><u>the </u><u>given </u><u>denominators </u>

\sf{ = \:}{\sf{\dfrac{ 35 +  12 }{30}}}

\sf{ =\: }{\sf{\red{\dfrac{ 47 }{30}}}}

Hence, The answer is 47/30

<h3><u>Solution </u><u>(</u><u> </u><u>b</u><u>) </u><u> </u><u>:</u><u>-</u></h3>

\bold{\dfrac{ 1}{7}}{\bold{ + }}{\bold{\dfrac{ 1}{8}}}

  • <u>By taking LCM of the given denominators </u>

\sf{ =\: }{\sf{\dfrac{ 8 + 7 }{56}}}

\sf{ =\: }{\sf{\red{\dfrac{ 15}{56}}}}

Hence, The answer is 15/56

<h3><u>Solution </u><u>(</u><u> </u><u>c</u><u>) </u><u> </u><u>:</u><u>-</u></h3>

\bold{\dfrac{ 7}{13}}{\bold{ + }}{\bold{\dfrac{ 5}{10}}}

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\sf{=\:}{\sf{\dfrac{ 70 + 65 }{130}}}

\sf{ = \:}{\sf{\dfrac{ 135}{130}}}

\sf{ =\:}{\sf{\red{\dfrac{ 27}{26}}}}

Hence, The answer is 27/26

<h3><u>Solution </u><u>(</u><u> </u><u>d</u><u>) </u><u> </u><u>:</u><u>-</u></h3>

\bold{\dfrac{ 7}{5}}{\bold{ - }}{\bold{\dfrac{ 1}{3}}}

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\bold{\dfrac{ 8}{7}}{\bold{ - }}{\bold{\dfrac{ 9}{11}}}

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\sf{=\:}{\sf{\dfrac{ 88 - 63}{77}}}

\sf{=\:}{\sf{\red{\dfrac{ 25}{77}}}}

Hence, The answer is 25/77

<h3><u>Solution </u><u>(</u><u> </u><u>f</u><u>) </u><u>:</u><u>-</u></h3>

\bold{\dfrac{ 11}{4}}{\bold{ - }}{\bold{\dfrac{ 1}{9}}}

  • <u>By taking LCM of the given denominators</u>

\sf{=\:}{\sf{\dfrac{ 99 - 4}{36}}}

\sf{ =\: }{\sf{\red{\dfrac{ 95}{36}}}}

Hence, The answer is 95/36

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