<em>Hexagonal</em> implies that the <em>traffic sign</em> has six straight sides. But <u>dilating</u> it changes its <em>length</em> of sides, but not its angles. So that the <em>statement</em> that is <u>true</u> is option B.
i.e B. The <u>dilated</u> sign will have corresponding line segments that are <em>proportional</em> to those of the pre-image and <u>corresponding</u> angles that are congruent to that of the pre-image.
Dilation involves <u>increasing</u> or <u>decreasing</u> the line segments of a given shape by a <em>scale factor</em>. This process do not affect the measure of the internal <u>angles</u> of the shape.
Given a <u>hexagonal</u> traffic sign in the question, this implies that the traffic sign has six sides. <u>Dilating</u> it by a scale factor of 2.5 about its center would affect its <em>length</em> of sides. So that the <em>statement</em> that is <u>true</u> is option B.
i.e B. The dilated sign will have <u>corresponding</u> line segments that are proportional to those of the pre-image and <em>corresponding</em> angles that are congruent to that of the pre-image.
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The slope of Anya’s line on the graph is 3
<h3>How to determine the slope of the line?</h3>
The equation is given as:
(y−2)=3(x−1)
Remove brackets
y − 2 = 3x − 3
Add 2 to both sides
y = 3x − 1
A linear equation is represented as:
y = mx + c
Where m represents the slope;
By comparison, m = 3
Hence, the slope of Anya’s line is 3
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Answer:
Step-by-step explanation:
(3,0),(4,1) ⇒ (x₁,y₁),(x₂,y₂)
to find the equation of the line
y-y₁= {(y₂-y₁)/(x₂-x₁)}(x-x₁)
y-0= [(1-0)/(4-3)] (x-3)
y-0 = 1/1(x-3)
y-0 = x-3
y= x-3+0
y=x-3
compare to y=mx+c, where m is the gradient and c is the intercept on y-axis
m=1, c=-3
∴the y-intercept of the line is -3
Answer:
d
Step-by-step explanation:
yes
Method 1: Realize that the desired equation will look exactly the same as the given equation 3x − 4y = 6, except that the constant will be different.
Thus, the equation of the new line is 3(-2) − 4(6) = C, where C comes out to 30.
Then the new line is 3x - 4y = 30.
