The chances that NEITHER of these two selected people were born after the year 2000 is 0.36
<h3>How to determine the probability?</h3>
The given parameters are:
Year = 2000
Proportion of people born after 2000, p = 40%
Sample size = 2
The chances that NEITHER of these two selected people were born after the year 2000 is calculated as:
P = (1- p)^2
Substitute the known values in the above equation
P = (1 - 40%)^2
Evaluate the exponent
P = 0.36
Hence, the chances that NEITHER of these two selected people were born after the year 2000 is 0.36
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Answer:
72 cubic ft
Step-by-step explanation:
To find volume you multiply length × width × height
Length is 4, width is 6 and height is 3
4×6×3= 72
The test statistic z will be equal to -0.946 and it shows that there is no significant difference in the proportion of rehires between full time and part time.
Given sample sizes of 833 and 386 and result of samples 434 and 189.

Proportion of full time=434/833=0.52
Proportion of part time=189/386=0.49.
Difference in proportion =0.52-0.49
TTF- i∈ rho=0
TTF+i∈ rho≠0.
Mean of difference=0.03
Z=(X-μ)/σ
σ=
=0.0317
σ=0.0317
z=(0-0.03)/0.0317
=-0.03/0.0317
=-0.317
p value will be =0.1736.
Because p value is greater than 0.01 so we will accept the null hypothesis which shows that there is no significant difference in the proportions.
Hence there is no significant difference in the proportion of rehires between full time and part time.
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Answer:
946.353
Step-by-step explanation:
X^2-8x-20 and if you rewrite that it’s (x-10) (x+2)