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Anton [14]
3 years ago
10

How to understand the word problem well in the math?​

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0
<h2><u>hello</u></h2>

<h3>your question is how can u understand world problem</h3><h3 /><h3>The very first thing is that read the question</h3><h3>Reading the questions doesnt mean that just looking at it and staring but you should the question line by line. still if cant understand try to read in your own language</h3>

<h3>And my suggestion is that before going for exam you should be well prepared all the world problem given in text and you can also refer to the net for extra questions. practice more and more as you can</h3><h3></h3><h3>And when you are reading the word problems . your concepts should be clear like a diamond like you should know from which chapter it is etc </h3>

<h3><u>hope this helps</u></h3><h3><u>:)</u></h3>
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Quien me ayuda? pls!!!
posledela

Answer:

The answer is B

Step-by-step explanation:

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Leo is running in a 5-kilometer race along a straight path. If he is at the midpoint of the path, how many kilometers does he ha
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Let f(x)=8x^3 -22x^2 and g(x)=4x-3. find f(x)/g(x)
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3 years ago
1.- What is 'a' for this hyperbola?
SpyIntel [72]

Answer:

The standard form of a hyperbola with vertices and foci on the x-axis:

\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1

where:

  • center:  (h, k)
  • vertices:  (h+a, k) and (h-a,k)
  • Foci:  (h+c, k) and (h-c, k) where the value of c is c² = a² + b²
  • Slopes of asymptotes: \pm\left(\dfrac{b}{a}\right)

<h3><u>Part 1</u></h3>

The center of the given hyperbola is (0, 0), therefore:

\implies \dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1

Therefore (\pm a,0) are the vertices.  From inspection of the graph, a=2.

<h3><u>Part 2</u></h3>

Choose two points on the asymptote with the positive slope:

(0, 0) and (4, 6)

Use the slope formula to find the slope:

\sf slope\:(m)=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{6-0}{4-0}=\dfrac{3}{2}

<h3><u>Part 3</u></h3>

Use the <u>slopes of asymptotes</u> formula, compare with the slope found in part 2:

\implies \dfrac{b}{a}=\dfrac{3}{2}

Therefore, b=3

<h3><u>Part 4</u></h3>

Substitute the found values of a and b into the equation from part 1:

\implies \dfrac{x^2}{2^2}-\dfrac{y^2}{3^2}=1

\implies \dfrac{x^2}{4}-\dfrac{y^2}{9}=1

4 0
2 years ago
Jun and deron are applying for summer jobs at a local restaurant. after interviewing them, the restaurant owner says, "the proba
mr Goodwill [35]
<span>As restaurant owner The probability of hiring Jun is 0.7 => p(J) The probability of hiring Deron is 0.4 => p(D) The probability of hiring at least one of you is 0.9 => p(J or D) We have a probability equation: p(J or D) = p(J) + p(D) - p(J and D) => 0.9 = 0.7 + 0.4 - p(J and D) p(J and D) = 1.1 - 0.9 = 0.2 So the probability that both Jun and Deron get hired is 0.2.</span>
6 0
3 years ago
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