The ratio that isn’t equivalent to the others is 10/12 because 7/8 and 21/24 are equivalent to eachother
Answer:
Can you plssssssssssss help me
Can you do plsssssssss help me
Answer:
The age of each person is:
- Jess is <u>21</u> years old.
- Mac is <u>66</u> years old.
Step-by-step explanation:
To solve this problem you must make two equations. First, we name Jess and Mac as variables:
j = Jess age.
m = Mac age.
Now we make the equations, the first equation has the information "Jess is 12 years less than half as old as Mac":
1. ![j=(\frac{m}{2})-12](https://tex.z-dn.net/?f=j%3D%28%5Cfrac%7Bm%7D%7B2%7D%29-12)
The second equation has the information "The sum of their age is 87":
2. ![j+m=87](https://tex.z-dn.net/?f=j%2Bm%3D87)
Now, we replace the first equation in the second one:
And we operate:
We clear the variable m:
How we know Mac's age is 66 years old, we can identify Jess' age with the second equation:
We replace the value of m:
And clear the variable j:
In the end, Jess's age is 21 years old.
Answer:
a= 135
Step-by-step explanation:
18*15=135
<h2>
Answer:</h2>
The answer is 16.
<h2>
Step-by-step explanation:</h2>
Since the 8x is positive, the equation must have y as a positive number.
Let's see this!
An easy way to complete the square if you have the constants for x2 and
But not the non-variable number is to divide the x constant, and then square it.
Example:
![\frac{8x}{2} \\\\4^2=16\\](https://tex.z-dn.net/?f=%5Cfrac%7B8x%7D%7B2%7D%20%5C%5C%5C%5C4%5E2%3D16%5C%5C)
The last number must be 16. Let's check it.
![(x+4)^2=x^2+8x+16](https://tex.z-dn.net/?f=%28x%2B4%29%5E2%3Dx%5E2%2B8x%2B16)