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3 years ago

Is 3/4 thicker than 7/8

2 answers:

8 0

You need to convert the 3/4 to the same common denominator of 8 as the 7/8.
3/4 = 6/8
7/8 - 6/8 = 1/8
So no 3/4 is not larger, it's smaller by 1/8.

zmey [24]3 years ago

3 0

No it is not because 3/4 is the same as 6/8 and it is not thicker than 7/8

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What is the simplified value of the exponential expression 27 1/3 ?

kicyunya [14]

Answer:

the correct answer is 3

hope it helps

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8 0

3 years ago

pedro has 6 packs of gum with p pieces in each pack he had a total of 72 pieces of gum decide whether each equation represents t

Serga [27]

Answer:

$6p = 72$ --- The equation

The solution is 12 packs i.e. p = 12

Step-by-step explanation:

No options given. So, I will solve generally.

Given

$Packs = 6$

$Quantity = p$ per pack

$Total = 72$

Required

Determine the equation

This is calculated using:

$Packs * Quantity = Total$

$6 * p = 72$

$6p = 72$

Divide both sides by 6

$p = 12$

4 0

3 years ago

If marching bands vary from 21 to 49 player, which numbers of players can be arranged in the greatest number of rectangles?

ANEK [815]

Hmm. a rectangle?ok then, least number of rectangles needed-6.
. . .
. . . ( rectangle)
so, 6 x 8=48(greatest multiple of 6 from between 21 and 49)
48 players are most, so 8 rectangles

5 0

3 years ago

You pull a sled across a horizontal frictionless patch of snow. If your pulling force is in the same direction as the sled's dis

nexus9112 [7]

Answer:

The kinetic energy of the sled is going to increase by 18.75%

Step-by-step explanation:

The work W realized by a Force F is given by:

$W=F_x*x$

Where x is the displacement and $F_x$ is the component of the force that is parallel to the displacement.

Additionally, the work is equal to the change in the kinetic energy

$W=K_f-K_i$

If your pulling force is in the same direction as the sled's displacement, we can said that: $F=F_x$

And if increases the kinetic energy of the sled by 27%, we can said that:

$K_f-K_i=0.27K_i$

So, we can formulate the following equation:

$W=F*x\\W=0.27K_i\\\\F*x=0.27K_i$ (1)

On the other hand, if the pulling force acted at an angle of 46° above the horizontal, the work is:

$W=F_x*x=Fcos(46)*x=F*x*cos(46)$ (2)

Then, replacing (1) in (2), we get:

$W=F*x*cos(46)=0.27K_i*cos(46) = 0.1875K_i$

Finally, the kinetic energy increase by 18.75% because:

$W=K_f-K_i\\W=0.1875K_i\\\\K_f-K_i=0.1875K_i$

5 0

3 years ago

Can someone help me out?

Anna35 [415]

Answer:

I need more information

Step-by-step explanation:

4 0

4 years ago