Answer:
c)55
Step-by-step explanation:
Answer:B
Step-by-step explanation:
Answer:
In a quadratic equation of the shape:
y = a*x^2 + b*x + c
we hate that the discriminant is equal to:
D = b^2 - 4*a*c
This thing appears in the Bhaskara's formula for the roots of the quadratic equation:

You can see that the determinant is inside a square root, this means that if D is smaller than zero we will have imaginary roots (the graph never touches the x-axis)
If D = 0, the square root term dissapear, and this implies that both roots of the equation are the same, this means that the graph touches the x axis in only one point, wich coincides with the minimum/maximum of the graph)
If D > 0 we have two different roots, so the graph touches the x-axis in two different points.
Answer:
x = 1 y = 2
Step-by-step explanation:
x + 3y = 7
- Subtract x from both sides.
3y = -x + 7
- Divide both sides by 3 to isolate the variable.
y = -1/3x + 7/3
- Plug the value of y into the other equation.
3x + 4(-1/3x + 7/3) = 11
3x - 4/3x + 28/3 = 11
- Add like terms.
5/3x + 28/3 = 11
5/3x = 5/3
x = 1
- Plug the value of x into the equation.
x + 3y = 7
(1) + 3y = 7
3y = 6
y = 2
The dilation factor Sophia is using appears to be
(image coordinate)/(original coordinate) = -9/-3 = 15/5 = 3
Then the problem tells us
(pre-image point)×3 = (3, 1)
so we conclude
(pre-image point) = (3, 1)/3 = (1, 1/3)