Question

If mc020-1.jpg and mc020-2.jpg, what is the domain of mc020-3.jpg?

Answer 1

Answer:

we have

f(x)=x+7

g(x)=\frac{1}{x-13}

(fog)(x)=[\frac{1}{x-13}]+7

we know that

the denominator cannot be zero, therefore the value of x cannot be 13

The domain are all real numbers except the number 13

therefore

the answer is the option

{x|≠13}

Answer 2

we have

$f(x)=x+7$

$g(x)=\frac{1}{x-13}$

$(fog)(x)=[\frac{1}{x-13}]+7$

we know that

the denominator cannot be zero, therefore the value of x cannot be $13$

The domain are all real numbers except the number $13$

therefore

the answer is the option

{x|≠13}