Yasim is Albert who ran the race at a time that was 15.7 seconds shorter, So, Yasim is the student who improved the most by decreasing the time needed to run the race.
<h2>Given that,</h2>
Coach Burns charted the change in his runners' 5K times from the first race of the year to the second race of the year.
<h3>We have to
find,</h3>
Which student improved the most by decreasing the time needed to run the race?
<h3>
According to the
question,</h3>
Coach Burns charted the change in his runners' 5K times from the first race of the year to the second race of the year.
In the given option Yasim has the lowest value of the time which is -37.5 seconds.
Yasim was the most improved student because Yasim ran the second race in a time that was 37.4 seconds shorter than the first race.
Following Yasim is Albert who ran the race at a time that was 15.7 seconds shorter.
At the third place in improvement is Cody who actually was worse off than the first race along with the 4th place Hannah.
Hence, Yasim students improved the most by decreasing the time needed to run the race.
For more details about the Equation refer to the link given below.
brainly.com/question/3842749
Answer:
20ft × 17ft
Step-by-step explanation:
(20-x)(23-x) = (20×23) - 120
460 - 43x + x² = 460 - 120
x² - 43x + 120 = 0
x² - 40x - 3x + 120 = 0
x(x - 40) - 3(x - 40) = 0
(x - 40)(x - 3) = 0
x = 3, 40
x = 3
New dimensions:
(23-3) × (20-3)
20 × 17
Answer: A
Step-by-step explanation:
Answer:
C. 
Step-by-step explanation:
Using this formula will help you determine which <em>rate of change</em> [<em>slope</em>] is the greatest:
This tells you that when −x is multiplied by −4, you get 4, and since 2 is less than 4, you have your answer.
I am joyous to assist you anytime.
The answer should be d because the circumference is 2 time pie r squared
