<em>Given - a+b+c = 0</em>
<em>To prove that- </em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<em>Now we know that</em>
<em>when x+y+z = 0,</em>
<em>then x³+y³+z³ = 3xyz</em>
<em>that means</em>
<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>
<em>Lets solve for LHS</em>
<em>LHS = a²/bc + b²/ac + c²/ab</em>
<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>
<em>by multiplying missing denominators,</em>
<em>now take common abc from denominator and you'll get,</em>
<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>
<em>Comparing one and two we can say that</em>
<em>(a³+b³+c³)/abc = 3</em>
<em>Hence proved,</em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
equilateral
Step-by-step explanation:
all of the side lengths are the same along with the angles
The answer should be 0.001703578
Answer:
- none
- none
- x ≥ 4
Step-by-step explanation:
The restrictions placed on the independent variable in a function are those necessary to ensure that the function is defined for all allowed values of that variable.
In the graphs of problems 1) and 2), we see that the functions are defined for all values of x, so there are no restrictions.
__
3. For the function ...

the value under the radical cannot be negative. The square root function is not defined for negative values, so the restriction is ...
x -4 ≥ 0
x ≥ 4 . . . . . . . add 4 to both sides of the inequality
<h3> Learning task 1</h3>
1. <u> </u><u> </u><u>3</u><u>.</u><u> </u><u> </u> 3. <u> </u><u> </u><u>1</u><u>. </u><u> </u>
4. 2
2. <u> </u><u> </u><u> </u><u>5</u><u>.</u><u> </u> 4. <u> </u><u> </u><u>6</u><u>. </u><u> </u>
9. 13
5. <u> </u><u> </u><u> </u><u>3</u><u>. </u> 6. <u> </u><u> </u><u> </u><u>7</u><u>. </u><u> </u>
5. 9
Step by step explanation:
hopefully that's help