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Furkat [3]
3 years ago
9

I NEED THIS ASAP PLEASE

Mathematics
1 answer:
ella [17]3 years ago
5 0

Answer:

Step-by-step explanation:

This is modeled after an exponential function which, at its simplest, is

y=a(b)^x where, for us and in this particular situation, y is the final height, a is the initial height, b is the rate of growth or decline, and x is the number of bounces. We know the initial height is 20, but we need to find the rate of decline. Rewriting the formula to model a rate of decay or decline is

y=a(1-r)^x, or more closely related to our circumstances:

H=20(1-.8)^n and simplifying that a bit:

H=20(.2)^n, choice D.

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80 points! Look at pic attached. I will mark brainiest if you explain your reasoning good. Random answers will be reported.
gregori [183]

Answer: No, your friend is not correct. You cannot use a similarity transformation to turn a square into a rectangle. Here's why:

1) If you used a similarity transformation, the size and position of the shape would change, but the shape itself remains the same.

2) Squares and rectangles are NOT similar.* Referring to the first point I listed, if the shapes are not similar, then a similarity transformation cannot be used to turn one shape into another.

<em>*Similar means that the edges are proportional to one another, such as a square with sides of 4 meters vs a square with sides of 2 meters: the sides are different lengths, but the shape is the same.</em>

I hope this helps! Please feel free to comment below if you need any clarification. Have a good day, and good luck on your assignment. :)

7 0
3 years ago
What would be the equation for this and the answer
atroni [7]

Answer:

The answer is k=61-26

Step-by-step explanation: This is because if you were to subtract 61 from 26 you will get 35. If you take 35 and add it to 26 you will get 61.

4 0
3 years ago
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¿Cómo simplifico 57/10?
Nonamiya [84]

Answer:

Step-by-step explanation:

57/10 cannot be simplified

but the decimal answer is 5.7

3 0
3 years ago
QUESTIUN 5
IRINA_888 [86]
It has to be true because
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Given two different circles O and Q, which of the following cases presents two circles with no (zero) common tangents?
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Concentric circles because if a line is tangent to one circle, it would only intersect teh other 
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