What is the y-value of the point of intersection of y=2sinx-cosx and y=cosx over the interval 0≤x≤pi/2 ? a. 0 b. (square root of
2)/2 c. (square root of 3)/2 d. 1
2 answers:
We have that
<span>y=2sinx-cosx
y=cosx
</span>over the interval 0≤x≤pi/2-------> 0≤x≤1.57
using a graph tool
see the attached figure
the solution in the given interval is the point (pi/4, 0.707)
the y-value of the point of intersection is 0.707 -----> √2/2
the answer is the option
<span>b. (square root of 2)/2</span>
<span>y=2sinx-cosx
y=cosx
</span>over the interval 0≤x≤pi/2-------> 0≤x≤1.57
using a graph tool
see the attached figure
the solution in the given interval is the point (pi/4, 0.707)
the y-value of the point of intersection is 0.707 -----> √2/2
the answer is the option
<span>b. (square root of 2)/2</span>
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Based on the triangle sum theorem, exterior angle theorem, the true statements are:
m∠5 + m∠6 = 180°
m∠2 + m∠3 = m∠6
m∠2 + m∠3 + m∠5 = 180°
<h3>What is the Triangle Sum Theorem and the Exterior Angle Theorem?</h3>According to the triangle sum theorem, m∠2 + m∠3 + m∠5 = 180°.
Also, based on the exterior angle theorem, m∠2 + m∠3 = m∠6.
∠5 and ∠6 are a pair of linear angles, therefore: m∠5 + m∠6 = 180°.
In summary, the true statements about the diagram given are:
- m∠5 + m∠6 = 180°
- m∠2 + m∠3 = m∠6
- m∠2 + m∠3 + m∠5 = 180°
Learn more about the triangle sum theorem on:
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