What is the y-value of the point of intersection of y=2sinx-cosx and y=cosx over the interval 0≤x≤pi/2 ? a. 0 b. (square root of
2)/2 c. (square root of 3)/2 d. 1
2 answers:
We have that
<span>y=2sinx-cosx
y=cosx
</span>over the interval 0≤x≤pi/2-------> 0≤x≤1.57
using a graph tool
see the attached figure
the solution in the given interval is the point (pi/4, 0.707)
the y-value of the point of intersection is 0.707 -----> √2/2
the answer is the option
<span>b. (square root of 2)/2</span>
<span>y=2sinx-cosx
y=cosx
</span>over the interval 0≤x≤pi/2-------> 0≤x≤1.57
using a graph tool
see the attached figure
the solution in the given interval is the point (pi/4, 0.707)
the y-value of the point of intersection is 0.707 -----> √2/2
the answer is the option
<span>b. (square root of 2)/2</span>
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A.
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- It was vertically compressed by a factor of 3, hence
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A.
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Answer:
nth term = 7n - 2
Step-by-step explanation:
a = first term = 5
d = common difference = second term - first term
= 12 - 5 =7
d = 7
a + (n-1)d
= 5 + (n -1)7
= 5 + 7n - 7 {add like terms}
= 7n - 2