What is the y-value of the point of intersection of y=2sinx-cosx and y=cosx over the interval 0≤x≤pi/2 ? a. 0 b. (square root of
2)/2 c. (square root of 3)/2 d. 1
2 answers:
We have that
<span>y=2sinx-cosx
y=cosx
</span>over the interval 0≤x≤pi/2-------> 0≤x≤1.57
using a graph tool
see the attached figure
the solution in the given interval is the point (pi/4, 0.707)
the y-value of the point of intersection is 0.707 -----> √2/2
the answer is the option
<span>b. (square root of 2)/2</span>
<span>y=2sinx-cosx
y=cosx
</span>over the interval 0≤x≤pi/2-------> 0≤x≤1.57
using a graph tool
see the attached figure
the solution in the given interval is the point (pi/4, 0.707)
the y-value of the point of intersection is 0.707 -----> √2/2
the answer is the option
<span>b. (square root of 2)/2</span>
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Answer:
C
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 32² = 48²
x² + 1024 = 2304 ( subtract 1024 from both sides )
x² = 1280 ( take the square root of both sides )
x =
=
= ×
= 16 → C