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lorasvet [3.4K]
3 years ago
15

If X = 13 units, Y = 15 units, and h = 11 units, what is the area of the parallelogram shown above?

Mathematics
1 answer:
Sedbober [7]3 years ago
7 0

Answer:

the area of the parallelogram = base times the height

For the given parallelogram :

x = 8 units, y = 13 units, and h = 11 units

1) If x is the perpendicular to h

So, the base = 8 and the height = 11

So, the area = 8 * 11 = 88 square units

2) If y is the perpendicular to h

So, the base = 13 and the height = 11

So, the area = 13 * 11 = 143 square units

Step-by-step explanation:

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(Простите, пожалуйста, мой английский. Русский не мой родной язык. Надеюсь, у вас есть способ перевести это решение. Если нет, возможно, прилагаемое изображение объяснит достаточно.)

Use the shell method. Each shell has a height of 3 - 3/4 <em>y</em> ², radius <em>y</em>, and thickness ∆<em>y</em>, thus contributing an area of 2<em>π</em> <em>y</em> (3 - 3/4 <em>y</em> ²). The total volume of the solid is going to be the sum of infinitely many such shells with 0 ≤ <em>y</em> ≤ 2, thus given by the integral

\displaystyle 2\pi \int_0^2 y \left(3-\frac34 y^2\right) \,\mathrm dy = 2\pi \left(\frac32 y^2 - \frac3{16} y^4\right)\bigg|_0^2 = 6\pi

Or use the disk method. (In the attachment, assume the height is very small.) Each disk has a radius of √(4/3 <em>x</em>), thus contributing an area of <em>π</em> (√(4/3 <em>x</em>))² = 4<em>π</em>/3 <em>x</em>. The total volume of the solid is the sum of infinitely many such disks with 0 ≤ <em>x</em> ≤ 3, or by the integral

\displaystyle \pi \int_0^3 \left(\sqrt{\frac43x}\right)^2 \,\mathrm dx = \frac{2\pi}3 x^2\bigg|_0^3 = 6\pi

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